- | WGU D335 Intro to Python
WGU D335 Intro to Python | OA | Objective Assessment Latest Questions and 100% Correct Answers 2025/2026 Updated
Create a solution that accepts three integer inputs representing the number of times an employee travels to a job site. Output the total distance traveled to two decimal places given the following miles per employee commute to the job site. Output the total distance traveled to two decimal places given the following miles per employee commute to the job site: Employee
A: 15.62 miles Employee
B: 41.85 miles Employee
C: 32.67 miles
times_traveledA = int(input()) times_traveledB = int(input()) times_traveledC = int(input()) employeeA = 15.62 #miles employeeB = 41.85 #miles employeeC = 32.67 #miles distance_traveledA = times_traveledA * employeeA distance_traveledB = times_traveledB * employeeB distance_traveledC = times_traveledC * employeeC total_miles_traveled = distance_travele- dA + distance_traveledB + distance_trav- eledC print('Distance: {:.2f} miles'.format(total_miles_traveled))
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- | WGU D335 Intro to Python
Create a solution that accepts an input identifying the name of a text fle, for example, "WordTextFile1.txt". Each text fle contains three rows with one word per row. Using the open() function and write() and read() methods, interact with the input text fle to write a new sentence string composed of the three existing words to the end of the fle contents on a new line. Output the new fle contents.fle_name = input()
with open(fle_name, 'r') as f:
word1 = str(f.readline()).strip() word2 = str(f.readline()).strip() word3 = str(f.readline()).strip() f = open(fle_name, 'r') lines = f.read().splitlines() lines = ' '.join(lines) f.close() print(f'{word1}\n{word2}\n{word3}\n{lines
Create a solution that accepts an integer input representing any number of ounces. Output the converted total number of tons, pounds, and remaining ounces based on the input ounces value. There are 16 ounces in a pound and 2,000 pounds in a ton.number_ounces = int(input()) tons = number_ounces // (ounces_per_pound * pounds_per_ton) remaining_ounces = number_ounces % (ounces_per_pound * pounds_per_ton) pounds = remaining_ounces // ounces_per_pound remaining_ounces = remaining_ounces % ounces_per_pound
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