Portage Learning Chem 103 Actual Exam

Portage Learning Chem 103 Actual Exam 16 Final Latest Question and Answers Latest Updates 2023.

Exam 1-6

EXAM 1

Question 1

• Convert 1005.3 to exponential form and explain your answer.
• Convert 4.87 x 10-6 to ordinary form and explain your answer.

Answer:

• Convert 1005.3 = larger than 1 = positive exponent, move decimal 3 places = 1.0053 x

103

• Convert 4.87 x 10-6 =negative exponent =smaller than 1, move decimal 6 places =

0.00000487

• / 4

Question 2 Using the following information, do the conversions shown below, showing all work:

• ft = 12 inches 1 pound = 16 oz 1 gallon = 4 quarts

• mile = 5280 feet 1 ton = 2000 pounds 1 quart = 2 pints

kilo (= 1000) milli (= 1/1000) centi (= 1/100)

deci (= 1/10)

• 2.73 liters = ? ml 2. 8.6 pts = ? qts

Answer:

• / 4

• 2.73 liters x 1000 ml / 1 liter = 2730 ml
• 8.6 pts x 1 qt / 2 pts = 4.3 qts

Question 3

Do the conversions shown below, showing all work:

• 248oC = ? oK
• 25oF = ? oC
• 175oK = ? oF

Answer:

• 248oC + 273 = 521 oK oC → oK (make larger) +273

• 25oF - 32 ÷ 1.8 = -3.88 oC oF → oC (make smaller) -32

÷1.8

• 175oK - 273 = -98 oC x 1.8 + 32 = -144.4 oF oK → oC → oF

Question 4

Be sure to show the correct number of significant figures in each calculation. 3 / 4

• Show the calculation of the mass of a 17.9 ml sample of chloroform with density of 1.49

g/ml

• Show the calculation of the volume of 19.4 grams of cresol with density of 1.02 g/ml

Answer:

• M = D x V = 1.49 x 17.9 = 26.7 g
• V = M / D = 19.4 / 1.02 = 19.0 ml Question 5
• 1.35601 contains ? significant figures.
• 0.151 contains ? significant figures.

• 1.35601 + 0.151 = ? (give answer to correct number of significant figures)

Answer:

• 1.35601 contains 6 significant figures.

• 0.151 contains 3 significant figures.

• 1.35601 + 0.151 = 1.50701 = 1.507 (to the thousands place for 0.151)

Question 6

Classify each of the following as an element, compound, solution or heterogeneous mixture and explain your answer.

• / 4