OAR EXAM Questions with Complete Solutions (Latest 2025) 16 ounces - Correct Answers ✅1 pound
- pints - Correct Answers ✅1 gallon
- quarts - Correct Answers ✅1 gallon
2000 lbs - Correct Answers ✅1 ton Supplemental angle - Correct Answers ✅adds up to 180 degrees Complementary angle - Correct Answers ✅adds up to 90 degrees If 3 times x exceeds 1/3 of y by 9, which of the following is the equation that shows the relationship between x and y? - Correct Answers ✅3x-1/3*y=9 Questions about how fast people can do a job together?If the first painter can do the entire job in twelve hours and the second painter can do it in eight hours, then (this here is the trick!) the first guy can do 1/12 of the job per hour, and the second guy can do 1/8 per hour. How much then can they do per hour if they work together? - Correct Answers ✅Take each number of hours and use 1/x amount of hours. 1 / 3
OAR EXAM Questions with Complete Solutions (Latest 2025)
Example: To find out how much they can do together per
hour, I add together what they can do individually per hour:
1/12 + 1/8 = 5/24.They can do 5/24 of the job per hour. Now I'll let "t" stand for how long they take to do the job together.Then they can do 1/t per hour, so 5/24 = 1/t. Flip the equation, and you get that t = 24/5 = 4.8 hours.1/12 + 1/8 = 1/t 5/24 = 1/t 24/5 = t =4.8 hours One pipe can fill a pool 1.25 times faster than a second pipe.When both pipes are opened, they fill the pool in five hours.How long would it take to fill the pool if only the slower pipe is
used? - Correct Answers ✅hours to complete job:
fast pipe: f
slow pipe: 1.25f
together: 5
completed per hour:
fast pipe: 1/f 2 / 3
OAR EXAM Questions with Complete Solutions (Latest 2025)
slow pipe: 1/1.25f
together: 1/5
adding their labor:
1/f + 1/1.25f = 1/5
multiplying through by 5f:
- + 5/1.25 = f
- + 4 = f = 9
- / 3
Then 1.25f = 11.25, so the slower pipe takes 11.25 hours.How much pure acid must be added to 12 ounces of a 40% acid solution in order to produce a 60% acid solution? - Correct Answers ✅P1*V1 + P2*V2 = P3*V3 P1*V1 would be X*1 P2*V2 is volume of first*percentage of first P3*V3 = (X+volume of first solution)*volume of final solve for X 100x + 480 = 60(12+x), x=6