Write the chemical formula of each compound: (a) Titanium(IV) fluoride (c) Copper(II) oxide (b) Iron(III) oxide (d) Nickel(IV) sulfide
The Correct Answer and Explanation is:
Here are the chemical formulas for each compound, along with a brief explanation of how they are derived:
(a) Titanium(IV) fluoride
- Formula: TiF₄
Explanation:
- Titanium(IV) refers to titanium with a +4 charge (Ti⁴⁺).
- Fluoride is the anion formed from fluorine, which has a charge of -1 (F⁻).
- To balance the charges, four fluoride ions (F⁻) are needed to balance the +4 charge of titanium, resulting in the formula TiF₄.
(b) Iron(III) oxide
- Formula: Fe₂O₃
Explanation:
- Iron(III) refers to iron with a +3 charge (Fe³⁺).
- Oxygen typically forms an oxide ion with a -2 charge (O²⁻).
- To balance the charges, two Fe³⁺ ions and three O²⁻ ions are needed to make the compound neutral. This results in the formula Fe₂O₃.
(c) Copper(II) oxide
- Formula: CuO
Explanation:
- Copper(II) indicates copper with a +2 charge (Cu²⁺).
- Oxygen forms an oxide ion with a -2 charge (O²⁻).
- One Cu²⁺ ion pairs with one O²⁻ ion to balance the charges, giving the formula CuO.
(d) Nickel(IV) sulfide
- Formula: NiS₂
Explanation:
- Nickel(IV) means nickel has a +4 charge (Ni⁴⁺).
- Sulfide is the anion formed by sulfur, which has a -2 charge (S²⁻).
- To balance the charges, two sulfide ions (S²⁻) are needed to balance the +4 charge of nickel, leading to the formula NiS₂.
These formulas follow the rules of charge balance for ionic compounds, where the total positive charge is equal to the total negative charge.
