{"id":7033,"date":"2025-05-23T08:47:00","date_gmt":"2025-05-23T08:47:00","guid":{"rendered":"https:\/\/yaveni.com\/blog\/?p=7033"},"modified":"2025-05-23T08:47:06","modified_gmt":"2025-05-23T08:47:06","slug":"in-basic-solution-the-chromate-ion-cro42","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/in-basic-solution-the-chromate-ion-cro42\/","title":{"rendered":"In basic solution the chromate ion, CrO4^2-"},"content":{"rendered":"\n<p>In basic solution the chromate ion, CrO4^2-, can be converted to the chromite, CrO2- ion. The number of electrons gained or lost by the chromium atom is<\/p>\n\n\n\n<p>A. 0<br>B. 3 electrons lost<br>C. 2 electrons lost<br>D. 3 electrons gained<br>E. 2 electrons gained<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p><strong>Correct Answer: D. 3 electrons gained<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>To determine how many electrons are gained or lost by the <strong>chromium atom<\/strong>, we must analyze the change in the <strong>oxidation state<\/strong> of chromium in the two ions: <strong>chromate ion (CrO\u2084\u00b2\u207b)<\/strong> and <strong>chromite ion (CrO\u2082\u207b)<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Determine the oxidation state of chromium in <strong>CrO\u2084\u00b2\u207b<\/strong>.<\/h3>\n\n\n\n<p>The formula for the chromate ion is CrO\u2084\u00b2\u207b.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Oxygen typically has an oxidation state of <strong>\u20132<\/strong>.<\/li>\n\n\n\n<li>There are four oxygen atoms: 4 \u00d7 (\u20132) = <strong>\u20138<\/strong>.<\/li>\n\n\n\n<li>The total charge of the ion is <strong>\u20132<\/strong>, so we can set up the equation:<\/li>\n<\/ul>\n\n\n\n<p>Cr+(\u22128)=\u22122\u21d2Cr=+6\\text{Cr} + (-8) = -2 \\Rightarrow \\text{Cr} = +6<\/p>\n\n\n\n<p>So, chromium is in the <strong>+6 oxidation state<\/strong> in CrO\u2084\u00b2\u207b.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Determine the oxidation state of chromium in <strong>CrO\u2082\u207b<\/strong>.<\/h3>\n\n\n\n<p>The formula for the chromite ion is CrO\u2082\u207b.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Again, oxygen has an oxidation state of <strong>\u20132<\/strong>.<\/li>\n\n\n\n<li>Two oxygen atoms: 2 \u00d7 (\u20132) = <strong>\u20134<\/strong>.<\/li>\n\n\n\n<li>Total charge of the ion is <strong>\u20131<\/strong>, so:<\/li>\n<\/ul>\n\n\n\n<p>Cr+(\u22124)=\u22121\u21d2Cr=+3\\text{Cr} + (-4) = -1 \\Rightarrow \\text{Cr} = +3<\/p>\n\n\n\n<p>So, chromium is in the <strong>+3 oxidation state<\/strong> in CrO\u2082\u207b.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Compare the oxidation states<\/h3>\n\n\n\n<p>Chromium changes from:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>+6 in CrO\u2084\u00b2\u207b<\/strong><\/li>\n\n\n\n<li>to <strong>+3 in CrO\u2082\u207b<\/strong><\/li>\n<\/ul>\n\n\n\n<p>This is a <strong>reduction<\/strong>, because the oxidation number is decreasing. When an atom is reduced, it <strong>gains electrons<\/strong>. +6\u2192+3\u21d23&nbsp;electrons&nbsp;gained+6 \\rightarrow +3 \\Rightarrow \\text{3 electrons gained}<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion:<\/h3>\n\n\n\n<p>The chromium atom <strong>gains 3 electrons<\/strong> during this process.<\/p>\n\n\n\n<p>Thus, the correct answer is:<\/p>\n\n\n\n<p><strong>D. 3 electrons gained<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>In basic solution the chromate ion, CrO4^2-, can be converted to the chromite, CrO2- ion. The number of electrons gained or lost by the chromium atom is A. 0B. 3 electrons lostC. 2 electrons lostD. 3 electrons gainedE. 2 electrons gained The correct answer and explanation is : Correct Answer: D. 3 electrons gained Explanation: [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[],"tags":[],"class_list":["post-7033","post","type-post","status-publish","format-standard","hentry"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/7033","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=7033"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/7033\/revisions"}],"predecessor-version":[{"id":7034,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/7033\/revisions\/7034"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=7033"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=7033"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=7033"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}