{"id":47785,"date":"2025-07-02T15:45:37","date_gmt":"2025-07-02T15:45:37","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=47785"},"modified":"2025-07-02T15:45:38","modified_gmt":"2025-07-02T15:45:38","slug":"ping-pong-balls-are-numbered-1-20-with-no-repetition-of-any-of-the-numbers","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/ping-pong-balls-are-numbered-1-20-with-no-repetition-of-any-of-the-numbers\/","title":{"rendered":"ping pong balls are numbered 1-20, with no repetition of any of the numbers."},"content":{"rendered":"\n<p class=\"wp-block-paragraph\"> ping pong balls are numbered 1-20, with no repetition of any of the numbers. What is the probability of selecting one ball that is either odd or a number 4 ball? Select the correct answer below: 50% 5% 45% 55%<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"361\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/image-137.png\" alt=\"\" class=\"wp-image-47786\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/image-137.png 1024w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/image-137-300x106.png 300w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/image-137-768x271.png 768w\" sizes=\"auto, (max-width: 1024px) 100vw, 1024px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Here is a detailed explanation of how to arrive at this answer.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">This problem asks for the probability of a specific event when selecting a single ping pong ball from a set of 20. Probability is calculated as the ratio of the number of favorable outcomes to the total number of possible outcomes.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">First, let&#8217;s identify the total number of possible outcomes. There are 20 ping pong balls, each numbered uniquely from 1 to 20. Therefore, when selecting one ball, there are 20 possible outcomes.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Next, we need to determine the number of favorable outcomes. The question asks for the probability of selecting a ball that is &#8220;either odd or a number 4 ball&#8221;. This means we need to count how many balls meet this condition. We can break this down into two parts:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Count the odd-numbered balls:<\/strong>\u00a0We need to find all the odd numbers between 1 and 20. These are: 1, 3, 5, 7, 9, 11, 13, 15, 17, and 19. Counting these, we find there are 10 odd-numbered balls.<\/li>\n\n\n\n<li><strong>Count the number 4 ball:<\/strong>\u00a0There is only one ball with the number 4.<\/li>\n<\/ol>\n\n\n\n<p class=\"wp-block-paragraph\">The event is selecting a ball that is odd OR the number 4. Since the number 4 is an even number, it is not included in our count of odd numbers. This means the two events, selecting an odd ball and selecting the number 4 ball, are mutually exclusive; they cannot happen at the same time. Therefore, to find the total number of favorable outcomes, we simply add the number of outcomes for each condition.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Total favorable outcomes = (Number of odd balls) + (Number of balls with the number 4)<br>Total favorable outcomes = 10 + 1 = 11<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Now we can calculate the probability:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Probability = (Number of Favorable Outcomes) \/ (Total Number of Possible Outcomes)<br>Probability = 11 \/ 20<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">To express this probability as a percentage, we multiply the fraction by 100:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Percentage = (11 \/ 20) * 100%<br>Percentage = 0.55 * 100%<br>Percentage = 55%<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Thus, the probability of selecting one ball that is either odd or the number 4 is 55%.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-277.jpeg\" alt=\"\" class=\"wp-image-47795\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-277.jpeg 1024w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-277-300x300.jpeg 300w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-277-150x150.jpeg 150w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-277-768x768.jpeg 768w\" sizes=\"auto, (max-width: 1024px) 100vw, 1024px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>ping pong balls are numbered 1-20, with no repetition of any of the numbers. What is the probability of selecting one ball that is either odd or a number 4 ball? Select the correct answer below: 50% 5% 45% 55% The Correct Answer and Explanation is: Here is a detailed explanation of how to arrive [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-47785","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/47785","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=47785"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/47785\/revisions"}],"predecessor-version":[{"id":47796,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/47785\/revisions\/47796"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=47785"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=47785"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=47785"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}