{"id":47662,"date":"2025-07-02T14:43:53","date_gmt":"2025-07-02T14:43:53","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=47662"},"modified":"2025-07-02T14:43:54","modified_gmt":"2025-07-02T14:43:54","slug":"using-the-formula-ma-x-seconds-mas-add-the-missing-information","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/using-the-formula-ma-x-seconds-mas-add-the-missing-information\/","title":{"rendered":"Using the formula mA x seconds = mAs, add the missing information."},"content":{"rendered":"\n

Using the formula mA x seconds = mAs, add the missing information. Make sure you convert milliseconds to seconds where required! 300 mA at 20 millisecs mAs 100 mA at 2\/5 sec = mAs 400 mA at 0.15 sec= mAs mA at 30 millisecs = 60 mAs mA at 1\/40 sec = 5 mAs mA at 0.25 sec = 10 mAs 500 mA at sec = 25 mAs 100 mA at sec = 10 mAs 200 mA at sec = 75 mAs<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

Here are the correct answers to complete the table:<\/p>\n\n\n\n

300 mA at 20 millisecs<\/td>= 6<\/strong> mAs<\/td><\/tr>
100 mA at 2\/5 sec<\/td>= 40<\/strong> mAs<\/td><\/tr>
400 mA at 0.15 sec<\/td>= 60<\/strong> mAs<\/td><\/tr>
2000<\/strong> mA at 30 millisecs<\/td>= 60 mAs<\/td><\/tr>
200<\/strong> mA at 1\/40 sec<\/td>= 5 mAs<\/td><\/tr>
40<\/strong> mA at 0.25 sec<\/td>= 10 mAs<\/td><\/tr>
500 mA at 0.05<\/strong> sec<\/td>= 25 mAs<\/td><\/tr>
100 mA at 0.1<\/strong> sec<\/td>= 10 mAs<\/td><\/tr>
200 mA at 0.375<\/strong> sec<\/td>= 75 mAs<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

Explanation<\/h3>\n\n\n\n

The calculations are based on the fundamental formula for radiographic exposure: milliamperes (mA) \u00d7 exposure time (seconds) = milliampere-seconds (mAs)<\/strong>. This formula allows us to find any one of the three values if the other two are known. A critical step for some of these problems is converting milliseconds to seconds, which is done by dividing the number of milliseconds by 1000.<\/p>\n\n\n\n

Calculating mAs (Rows 1-3):<\/strong><\/p>\n\n\n\n

    \n
  • Row 1:<\/strong>\u00a0First, convert 20 milliseconds to seconds: 20 \u00f7 1000 = 0.02 seconds. Then, multiply by the mA: 300 mA \u00d7 0.02 s =\u00a06 mAs<\/strong>.<\/li>\n\n\n\n
  • Row 2:<\/strong>\u00a0Convert the fraction 2\/5 to a decimal: 2 \u00f7 5 = 0.4 seconds. Then, calculate the mAs: 100 mA \u00d7 0.4 s =\u00a040 mAs<\/strong>.<\/li>\n\n\n\n
  • Row 3:<\/strong>\u00a0The time is already in seconds. Simply multiply the values: 400 mA \u00d7 0.15 s =\u00a060 mAs<\/strong>.<\/li>\n<\/ul>\n\n\n\n

    Calculating mA (Rows 4-6):<\/strong><\/p>\n\n\n\n

    To find the missing mA value, we rearrange the formula to: mA = mAs \u00f7 seconds<\/strong>.<\/p>\n\n\n\n

      \n
    • Row 4:<\/strong>\u00a0Convert 30 milliseconds to seconds: 30 \u00f7 1000 = 0.03 seconds. Then, divide the mAs by the time: 60 mAs \u00f7 0.03 s =\u00a02000 mA<\/strong>.<\/li>\n\n\n\n
    • Row 5:<\/strong>\u00a0Convert the fraction 1\/40 to a decimal: 1 \u00f7 40 = 0.025 seconds. Then, solve for mA: 5 mAs \u00f7 0.025 s =\u00a0200 mA<\/strong>.<\/li>\n\n\n\n
    • Row 6:<\/strong>\u00a0The time is in seconds. Divide the mAs by the time: 10 mAs \u00f7 0.25 s =\u00a040 mA<\/strong>.<\/li>\n<\/ul>\n\n\n\n

      Calculating Seconds (Rows 7-9):<\/strong><\/p>\n\n\n\n

      To find the missing time in seconds, we again rearrange the formula to: seconds = mAs \u00f7 mA<\/strong>.<\/p>\n\n\n\n

        \n
      • Row 7:<\/strong>\u00a0Divide the mAs by the mA: 25 mAs \u00f7 500 mA =\u00a00.05 seconds<\/strong>.<\/li>\n\n\n\n
      • Row 8:<\/strong>\u00a0Divide the mAs by the mA: 10 mAs \u00f7 100 mA =\u00a00.1 seconds<\/strong>.<\/li>\n\n\n\n
      • Row 9:<\/strong>\u00a0Divide the mAs by the mA: 75 mAs \u00f7 200 mA =\u00a00.375 seconds<\/strong>.<\/li>\n<\/ul>\n\n\n\n
        \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

        Using the formula mA x seconds = mAs, add the missing information. Make sure you convert milliseconds to seconds where required! 300 mA at 20 millisecs mAs 100 mA at 2\/5 sec = mAs 400 mA at 0.15 sec= mAs mA at 30 millisecs = 60 mAs mA at 1\/40 sec = 5 mAs mA […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-47662","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/47662","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=47662"}],"version-history":[{"count":2,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/47662\/revisions"}],"predecessor-version":[{"id":47666,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/47662\/revisions\/47666"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=47662"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=47662"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=47662"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}