{"id":47458,"date":"2025-07-02T12:15:55","date_gmt":"2025-07-02T12:15:55","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=47458"},"modified":"2025-07-02T12:15:57","modified_gmt":"2025-07-02T12:15:57","slug":"draw-the-orbital-diagram-and-write-the-electron-configuration-for-selenium-and-use-it-to-identify-the-17th-23rd-and-33rd-electrons","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/draw-the-orbital-diagram-and-write-the-electron-configuration-for-selenium-and-use-it-to-identify-the-17th-23rd-and-33rd-electrons\/","title":{"rendered":"Draw the orbital diagram and write the electron configuration for Selenium and use it to identify the 17th, 23rd and 33rd electrons."},"content":{"rendered":"\n

Draw the orbital diagram and write the electron configuration for Selenium and use it to identify the 17th, 23rd and 33rd electrons. Make a table and write the four quantum numbers for each or these electrons using the table.<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

Of course. Here is the detailed solution for the electron configuration, orbital diagram, and quantum numbers for Selenium.<\/p>\n\n\n\n

Selenium (Se) is element number 34 on the periodic table, meaning a neutral atom has 34 electrons. To solve this problem, we will first determine its electron structure and then identify the quantum numbers for the specified electrons.<\/p>\n\n\n\n

Electron Configuration and Orbital Diagram<\/strong><\/h3>\n\n\n\n

We will fill the atomic orbitals according to the Aufbau principle, which dictates the order of filling based on increasing energy levels.<\/p>\n\n\n\n

Electron Configuration for Selenium (Se):<\/strong><\/p>\n\n\n\n

1s\u00b2 2s\u00b2 2p\u2076 3s\u00b2 3p\u2076 4s\u00b2 3d\u00b9\u2070 4p\u2074<\/p>\n\n\n\n

Orbital Diagram for Selenium (Se):<\/strong><\/p>\n\n\n\n

The diagram visually represents the electron configuration, showing the distribution of electrons within the orbitals. Arrows indicate electrons, with their direction representing spin. We apply Hund’s rule, which states that electrons will singly occupy each orbital in a subshell before any orbital is doubly occupied.<\/p>\n\n\n\n

1s:<\/strong> [\u2191\u2193]
2s:<\/strong> [\u2191\u2193]
2p:<\/strong> [\u2191\u2193] [\u2191\u2193] [\u2191\u2193]
3s:<\/strong> [\u2191\u2193]
3p:<\/strong> [\u2191\u2193] [\u2191\u2193] [\u2191\u2193]
4s:<\/strong> [\u2191\u2193]
3d:<\/strong> [\u2191\u2193] [\u2191\u2193] [\u2191\u2193] [\u2191\u2193] [\u2191\u2193]
4p:<\/strong> [\u2191\u2193] [ \u2191 ] [ \u2191 ]<\/p>\n\n\n\n

Identifying Specific Electrons<\/strong><\/h3>\n\n\n\n

To find the quantum numbers for the 17th, 23rd, and 33rd electrons, we count through the orbital diagram in the order of filling:<\/p>\n\n\n\n

    \n
  • 17th Electron:<\/strong>\u00a0The first 12 electrons fill the 1s, 2s, 2p, and 3s subshells. The 3p subshell holds electrons 13 through 18. Following Hund’s rule, the 13th, 14th, and 15th electrons are spin-up in each of the three p-orbitals. The 16th electron pairs with the first p-orbital (m_l = -1). Therefore, the\u00a017th electron<\/strong>\u00a0is the spin-down electron that pairs in the second p-orbital (m_l = 0) of the\u00a03p subshell<\/strong>.<\/li>\n\n\n\n
  • 23rd Electron:<\/strong>\u00a0The first 20 electrons fill up to the 4s subshell. The 3d subshell holds electrons 21 through 30. Following Hund’s rule, the first five electrons (21st to 25th) will be spin-up in each of the five d-orbitals. The\u00a023rd electron<\/strong>\u00a0is the third spin-up electron, located in the third d-orbital (m_l = 0) of the\u00a03d subshell<\/strong>.<\/li>\n\n\n\n
  • 33rd Electron:<\/strong>\u00a0The first 30 electrons fill up to the 3d subshell. The 4p subshell holds the final four electrons. The 31st, 32nd, and 33rd electrons will be spin-up in each of the three p-orbitals. The\u00a033rd electron<\/strong>\u00a0is the third spin-up electron, located in the third p-orbital (m_l = +1) of the\u00a04p subshell<\/strong>.<\/li>\n<\/ul>\n\n\n\n

    Quantum Numbers Table<\/strong><\/h3>\n\n\n\n

    The four quantum numbers describe the state of an electron:<\/p>\n\n\n\n

      \n
    • n (Principal Quantum Number):<\/strong>\u00a0Energy level or shell.<\/li>\n\n\n\n
    • l (Azimuthal Quantum Number):<\/strong>\u00a0Subshell shape (0=s, 1=p, 2=d).<\/li>\n\n\n\n
    • m_l (Magnetic Quantum Number):<\/strong>\u00a0Orbital orientation in space (-l to +l).<\/li>\n\n\n\n
    • m_s (Spin Quantum Number):<\/strong>\u00a0Electron spin (+1\/2 for up, -1\/2 for down).<\/li>\n<\/ul>\n\n\n\n

      Here is the table summarizing the quantum numbers for the identified electrons:<\/p>\n\n\n\n

      Electron<\/td>Principal (n)<\/td>Azimuthal (l)<\/td>Magnetic (m_l)<\/td>Spin (m_s)<\/td><\/tr>
      17th<\/strong><\/td>3<\/td>1<\/td>0<\/td>-1\/2<\/td><\/tr>
      23rd<\/strong><\/td>3<\/td>2<\/td>0<\/td>+1\/2<\/td><\/tr>
      33rd<\/strong><\/td>4<\/td>1<\/td>+1<\/td>+1\/2<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n
      \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

      Draw the orbital diagram and write the electron configuration for Selenium and use it to identify the 17th, 23rd and 33rd electrons. Make a table and write the four quantum numbers for each or these electrons using the table. The Correct Answer and Explanation is: Of course. Here is the detailed solution for the electron […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-47458","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/47458","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=47458"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/47458\/revisions"}],"predecessor-version":[{"id":47461,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/47458\/revisions\/47461"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=47458"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=47458"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=47458"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}