{"id":46791,"date":"2025-07-02T08:31:36","date_gmt":"2025-07-02T08:31:36","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=46791"},"modified":"2025-07-02T08:31:39","modified_gmt":"2025-07-02T08:31:39","slug":"how-many-atoms-of-carbon-are-present-in-6-43-grams-of-carbon-dioxide","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/how-many-atoms-of-carbon-are-present-in-6-43-grams-of-carbon-dioxide\/","title":{"rendered":"How many ATOMS of carbon are present in 6.43 grams of carbon dioxide"},"content":{"rendered":"\n<p>How many ATOMS of carbon are present in 6.43 grams of carbon dioxide? __atoms of carbon . 2. How many GRAMS of oxygen are present in 2.05 x 10^21 molecules of carbon dioxide? ___grams of oxygen .<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Let&#8217;s break this down step-by-step:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Question 1: How many atoms of carbon are present in 6.43 grams of carbon dioxide (CO\u2082)?<\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Molar Mass of CO\u2082<\/strong>:\n<ul class=\"wp-block-list\">\n<li>Carbon (C) has a molar mass of 12.01 g\/mol.<\/li>\n\n\n\n<li>Oxygen (O) has a molar mass of 16.00 g\/mol.<\/li>\n\n\n\n<li>The molar mass of CO\u2082 = (1 \u00d7 12.01) + (2 \u00d7 16.00) = 44.01 g\/mol.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Moles of CO\u2082<\/strong>:<br>To find the number of moles of CO\u2082, divide the given mass of CO\u2082 by the molar mass of CO\u2082: Moles\u00a0of\u00a0CO\u2082=6.43\u00a0g44.01\u00a0g\/mol\u22480.1465\u00a0mol\\text{Moles of CO\u2082} = \\frac{6.43 \\text{ g}}{44.01 \\text{ g\/mol}} \\approx 0.1465 \\text{ mol}Moles\u00a0of\u00a0CO\u2082=44.01\u00a0g\/mol6.43\u00a0g\u200b\u22480.1465\u00a0mol<\/li>\n\n\n\n<li><strong>Atoms of Carbon<\/strong>:<br>Since each molecule of CO\u2082 contains 1 atom of carbon, the number of moles of carbon atoms is the same as the moles of CO\u2082.<br>To find the number of carbon atoms, multiply the moles of carbon by Avogadro\u2019s number (6.022 \u00d7 10\u00b2\u00b3 atoms\/mol): Atoms\u00a0of\u00a0carbon=0.1465\u00a0mol\u00d76.022\u00d71023\u00a0atoms\/mol\u22488.82\u00d71022\u00a0atoms\\text{Atoms of carbon} = 0.1465 \\text{ mol} \\times 6.022 \\times 10^{23} \\text{ atoms\/mol} \\approx 8.82 \\times 10^{22} \\text{ atoms}Atoms\u00a0of\u00a0carbon=0.1465\u00a0mol\u00d76.022\u00d71023\u00a0atoms\/mol\u22488.82\u00d71022\u00a0atoms<\/li>\n<\/ol>\n\n\n\n<p><strong>Answer<\/strong>: There are approximately <strong>8.82 \u00d7 10\u00b2\u00b2 atoms of carbon<\/strong> in 6.43 grams of CO\u2082.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Question 2: How many grams of oxygen are present in 2.05 \u00d7 10\u00b2\u00b9 molecules of CO\u2082?<\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Molecules of CO\u2082 to Moles of CO\u2082<\/strong>:<br>To convert molecules of CO\u2082 to moles, use Avogadro\u2019s number: Moles\u00a0of\u00a0CO\u2082=2.05\u00d71021\u00a0molecules6.022\u00d71023\u00a0molecules\/mol\u22483.41\u00d710\u22123\u00a0mol\\text{Moles of CO\u2082} = \\frac{2.05 \\times 10^{21} \\text{ molecules}}{6.022 \\times 10^{23} \\text{ molecules\/mol}} \\approx 3.41 \\times 10^{-3} \\text{ mol}Moles\u00a0of\u00a0CO\u2082=6.022\u00d71023\u00a0molecules\/mol2.05\u00d71021\u00a0molecules\u200b\u22483.41\u00d710\u22123\u00a0mol<\/li>\n\n\n\n<li><strong>Moles of Oxygen<\/strong>:<br>Each molecule of CO\u2082 contains 2 atoms of oxygen, so the number of moles of oxygen atoms will be twice the moles of CO\u2082: Moles\u00a0of\u00a0oxygen=3.41\u00d710\u22123\u00a0mol\u00a0CO\u2082\u00d72=6.82\u00d710\u22123\u00a0mol\u00a0oxygen\\text{Moles of oxygen} = 3.41 \\times 10^{-3} \\text{ mol CO\u2082} \\times 2 = 6.82 \\times 10^{-3} \\text{ mol oxygen}Moles\u00a0of\u00a0oxygen=3.41\u00d710\u22123\u00a0mol\u00a0CO\u2082\u00d72=6.82\u00d710\u22123\u00a0mol\u00a0oxygen<\/li>\n\n\n\n<li><strong>Mass of Oxygen<\/strong>:<br>The molar mass of oxygen is 16.00 g\/mol, so to find the mass of oxygen: Mass\u00a0of\u00a0oxygen=6.82\u00d710\u22123\u00a0mol\u00d716.00\u00a0g\/mol=0.1091\u00a0g\\text{Mass of oxygen} = 6.82 \\times 10^{-3} \\text{ mol} \\times 16.00 \\text{ g\/mol} = 0.1091 \\text{ g}Mass\u00a0of\u00a0oxygen=6.82\u00d710\u22123\u00a0mol\u00d716.00\u00a0g\/mol=0.1091\u00a0g<\/li>\n<\/ol>\n\n\n\n<p><strong>Answer<\/strong>: There are approximately <strong>0.109 grams of oxygen<\/strong> in 2.05 \u00d7 10\u00b2\u00b9 molecules of CO\u2082.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Summary<\/strong>:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>The number of carbon atoms in 6.43 grams of CO\u2082 is approximately <strong>8.82 \u00d7 10\u00b2\u00b2<\/strong>.<\/li>\n\n\n\n<li>The mass of oxygen in 2.05 \u00d7 10\u00b2\u00b9 molecules of CO\u2082 is approximately <strong>0.109 grams<\/strong>.<\/li>\n<\/ol>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-185.jpeg\" alt=\"\" class=\"wp-image-46796\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-185.jpeg 1024w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-185-300x300.jpeg 300w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-185-150x150.jpeg 150w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-185-768x768.jpeg 768w\" sizes=\"auto, (max-width: 1024px) 100vw, 1024px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>How many ATOMS of carbon are present in 6.43 grams of carbon dioxide? __atoms of carbon . 2. How many GRAMS of oxygen are present in 2.05 x 10^21 molecules of carbon dioxide? ___grams of oxygen . The Correct Answer and Explanation is: Let&#8217;s break this down step-by-step: Question 1: How many atoms of carbon [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-46791","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/46791","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=46791"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/46791\/revisions"}],"predecessor-version":[{"id":46797,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/46791\/revisions\/46797"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=46791"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=46791"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=46791"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}