{"id":46707,"date":"2025-07-02T07:55:00","date_gmt":"2025-07-02T07:55:00","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=46707"},"modified":"2025-07-02T07:55:02","modified_gmt":"2025-07-02T07:55:02","slug":"write-the-chemical-formula-of-each-compound-2","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/write-the-chemical-formula-of-each-compound-2\/","title":{"rendered":"Write the chemical formula of each compound"},"content":{"rendered":"\n<p>Write the chemical formula of each compound: (a) Titanium(IV) fluoride (c) Copper(II) oxide (b) Iron(III) oxide (d) Nickel(IV) sulfide<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Here are the chemical formulas for each of the compounds:<\/p>\n\n\n\n<p><strong>(a) Titanium(IV) fluoride<\/strong><br>Formula: <strong>TiF\u2084<\/strong><\/p>\n\n\n\n<p>Explanation:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Titanium (IV) means that titanium has a charge of +4, as indicated by the Roman numeral IV.<\/li>\n\n\n\n<li>Fluoride (F) comes from fluorine, which has a charge of -1.<\/li>\n\n\n\n<li>To balance the charges, we need four fluoride ions (each with a -1 charge) to balance the +4 charge of titanium.<br>Thus, the formula is TiF\u2084.<\/li>\n<\/ul>\n\n\n\n<p><strong>(b) Iron(III) oxide<\/strong><br>Formula: <strong>Fe\u2082O\u2083<\/strong><\/p>\n\n\n\n<p>Explanation:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Iron (III) means that iron has a charge of +3.<\/li>\n\n\n\n<li>Oxygen (O) has a charge of -2.<\/li>\n\n\n\n<li>To balance the charges, we need two iron ions (each with a +3 charge) and three oxygen ions (each with a -2 charge). This results in a total charge of +6 from iron and -6 from oxygen, which are balanced.<br>Thus, the formula is Fe\u2082O\u2083.<\/li>\n<\/ul>\n\n\n\n<p><strong>(c) Copper(II) oxide<\/strong><br>Formula: <strong>CuO<\/strong><\/p>\n\n\n\n<p>Explanation:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Copper (II) means copper has a charge of +2.<\/li>\n\n\n\n<li>Oxygen (O) has a charge of -2.<\/li>\n\n\n\n<li>To balance the charges, one copper ion (+2) combines with one oxygen ion (-2), giving the formula CuO.<\/li>\n<\/ul>\n\n\n\n<p><strong>(d) Nickel(IV) sulfide<\/strong><br>Formula: <strong>NiS\u2082<\/strong><\/p>\n\n\n\n<p>Explanation:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Nickel (IV) means nickel has a charge of +4.<\/li>\n\n\n\n<li>Sulfide (S) comes from sulfur, which has a charge of -2.<\/li>\n\n\n\n<li>To balance the charges, two sulfide ions (each with a -2 charge) are needed to balance the +4 charge of nickel.<br>Thus, the formula is NiS\u2082.<\/li>\n<\/ul>\n\n\n\n<p>In summary, the key to writing the formulas is balancing the charges of the metal cation (positive ion) and the non-metal anion (negative ion) to ensure the overall charge is neutral.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-174.jpeg\" alt=\"\" class=\"wp-image-46712\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-174.jpeg 1024w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-174-300x300.jpeg 300w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-174-150x150.jpeg 150w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-174-768x768.jpeg 768w\" sizes=\"auto, (max-width: 1024px) 100vw, 1024px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Write the chemical formula of each compound: (a) Titanium(IV) fluoride (c) Copper(II) oxide (b) Iron(III) oxide (d) Nickel(IV) sulfide The Correct Answer and Explanation is: Here are the chemical formulas for each of the compounds: (a) Titanium(IV) fluorideFormula: TiF\u2084 Explanation: (b) Iron(III) oxideFormula: Fe\u2082O\u2083 Explanation: (c) Copper(II) oxideFormula: CuO Explanation: (d) Nickel(IV) sulfideFormula: NiS\u2082 Explanation: [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-46707","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/46707","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=46707"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/46707\/revisions"}],"predecessor-version":[{"id":46713,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/46707\/revisions\/46713"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=46707"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=46707"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=46707"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}