{"id":46695,"date":"2025-07-02T07:52:31","date_gmt":"2025-07-02T07:52:31","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=46695"},"modified":"2025-07-02T07:52:33","modified_gmt":"2025-07-02T07:52:33","slug":"write-the-chemical-formula-of-each-compound","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/write-the-chemical-formula-of-each-compound\/","title":{"rendered":"Write the chemical formula of each compound"},"content":{"rendered":"\n<p>Write the chemical formula of each compound: (a) Titanium(IV) fluoride (c) Copper(II) oxide (b) Iron(III) oxide (d) Nickel(IV) sulfide<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Here are the chemical formulas for each compound, along with a brief explanation of how they are derived:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">(a) Titanium(IV) fluoride<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Formula: TiF\u2084<\/strong><\/li>\n<\/ul>\n\n\n\n<p>Explanation:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Titanium(IV) refers to titanium with a +4 charge (Ti\u2074\u207a).<\/li>\n\n\n\n<li>Fluoride is the anion formed from fluorine, which has a charge of -1 (F\u207b).<\/li>\n\n\n\n<li>To balance the charges, four fluoride ions (F\u207b) are needed to balance the +4 charge of titanium, resulting in the formula TiF\u2084.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">(b) Iron(III) oxide<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Formula: Fe\u2082O\u2083<\/strong><\/li>\n<\/ul>\n\n\n\n<p>Explanation:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Iron(III) refers to iron with a +3 charge (Fe\u00b3\u207a).<\/li>\n\n\n\n<li>Oxygen typically forms an oxide ion with a -2 charge (O\u00b2\u207b).<\/li>\n\n\n\n<li>To balance the charges, two Fe\u00b3\u207a ions and three O\u00b2\u207b ions are needed to make the compound neutral. This results in the formula Fe\u2082O\u2083.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">(c) Copper(II) oxide<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Formula: CuO<\/strong><\/li>\n<\/ul>\n\n\n\n<p>Explanation:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Copper(II) indicates copper with a +2 charge (Cu\u00b2\u207a).<\/li>\n\n\n\n<li>Oxygen forms an oxide ion with a -2 charge (O\u00b2\u207b).<\/li>\n\n\n\n<li>One Cu\u00b2\u207a ion pairs with one O\u00b2\u207b ion to balance the charges, giving the formula CuO.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">(d) Nickel(IV) sulfide<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Formula: NiS\u2082<\/strong><\/li>\n<\/ul>\n\n\n\n<p>Explanation:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Nickel(IV) means nickel has a +4 charge (Ni\u2074\u207a).<\/li>\n\n\n\n<li>Sulfide is the anion formed by sulfur, which has a -2 charge (S\u00b2\u207b).<\/li>\n\n\n\n<li>To balance the charges, two sulfide ions (S\u00b2\u207b) are needed to balance the +4 charge of nickel, leading to the formula NiS\u2082.<\/li>\n<\/ul>\n\n\n\n<p>These formulas follow the rules of charge balance for ionic compounds, where the total positive charge is equal to the total negative charge.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-173.jpeg\" alt=\"\" class=\"wp-image-46703\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-173.jpeg 1024w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-173-300x300.jpeg 300w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-173-150x150.jpeg 150w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner5-173-768x768.jpeg 768w\" sizes=\"auto, (max-width: 1024px) 100vw, 1024px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Write the chemical formula of each compound: (a) Titanium(IV) fluoride (c) Copper(II) oxide (b) Iron(III) oxide (d) Nickel(IV) sulfide The Correct Answer and Explanation is: Here are the chemical formulas for each compound, along with a brief explanation of how they are derived: (a) Titanium(IV) fluoride Explanation: (b) Iron(III) oxide Explanation: (c) Copper(II) oxide Explanation: [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-46695","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/46695","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=46695"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/46695\/revisions"}],"predecessor-version":[{"id":46705,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/46695\/revisions\/46705"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=46695"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=46695"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=46695"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}