{"id":46529,"date":"2025-07-02T07:05:22","date_gmt":"2025-07-02T07:05:22","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=46529"},"modified":"2025-07-02T07:05:24","modified_gmt":"2025-07-02T07:05:24","slug":"draw-the-molecular-orbital-diagram-of-cs","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/draw-the-molecular-orbital-diagram-of-cs\/","title":{"rendered":"Draw the molecular orbital diagram of CS."},"content":{"rendered":"\n
Draw the molecular orbital diagram of CS. Determine bond order, magnetism, spin multiplicity, and HOMO\/LUMO.<\/p>\n\n\n\n
The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n
To draw the molecular orbital diagram of carbon monosulfide (CS), we need to consider the bonding between carbon (C) and sulfur (S). CS is a diatomic molecule and its molecular orbital diagram involves the combination of atomic orbitals of carbon and sulfur atoms.<\/p>\n\n\n\n
Steps for constructing the molecular orbital diagram:<\/h3>\n\n\n\n\n
Determine the electron configuration of atoms:<\/strong>
Carbon (C): 1s\u00b2 2s\u00b2 2p\u00b2<\/li>
Sulfur (S): 1s\u00b2 2s\u00b2 2p\u2076 3s\u00b2 3p\u2074<\/li><\/ul>Since sulfur is in the third period, its 3s and 3p orbitals will interact with carbon\u2019s 2s and 2p orbitals, respectively.<\/li>\n\n\n\n
Orbital interactions:<\/strong>\n
\n
The lowest-energy molecular orbitals are formed from the combination of the atomic 2s and 3s orbitals, followed by the 2p and 3p orbitals.<\/li>\n<\/ul>\n<\/li>\n\n\n\n
Fill the molecular orbitals:<\/strong> The molecular orbitals are arranged in increasing energy order (for a heteronuclear molecule like CS):
\u03c3(2p), \u03c3*(2p)<\/li><\/ul>Based on this, the total number of electrons in CS is 10 (from carbon) + 6 (from sulfur) = 16 electrons.<\/li>\n\n\n\n
Filling the molecular orbitals:<\/strong>\n
\n
2 electrons in \u03c3(2s) (bonding)<\/li>\n\n\n\n
2 electrons in \u03c3*(2s) (antibonding)<\/li>\n\n\n\n
2 electrons in \u03c3(3s) (bonding)<\/li>\n\n\n\n
2 electrons in \u03c3*(3s) (antibonding)<\/li>\n\n\n\n
4 electrons in \u03c0(2p) (bonding)<\/li>\n\n\n\n
2 electrons in \u03c0*(2p) (antibonding)<\/li>\n<\/ul>\n<\/li>\n\n\n\n
Determine bond order:<\/strong>\n
\n
Bond order = (number of bonding electrons – number of antibonding electrons) \/ 2<\/li>\n\n\n\n
Bond order = (2 + 2 + 4) – (2 + 2) \/ 2 = 4 \/ 2 = 2<\/li>\n<\/ul>\n<\/li>\n\n\n\n
Magnetism:<\/strong> CS has no unpaired electrons in its molecular orbitals, meaning it is diamagnetic<\/strong>.<\/li>\n\n\n\n
Spin multiplicity:<\/strong> The spin multiplicity is calculated as 2S + 1, where S is the total spin quantum number. Since all electrons are paired, S = 0, and the spin multiplicity is 1<\/strong> (singlet).<\/li>\n\n\n\n
HOMO and LUMO:<\/strong>\n
\n
The Highest Occupied Molecular Orbital (HOMO)<\/strong> is the \u03c0*(2p) orbital.<\/li>\n\n\n\n
The Lowest Unoccupied Molecular Orbital (LUMO)<\/strong> is the \u03c3*(2p) orbital.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n
Draw the molecular orbital diagram of CS. Determine bond order, magnetism, spin multiplicity, and HOMO\/LUMO. The Correct Answer and Explanation is: To draw the molecular orbital diagram of carbon monosulfide (CS), we need to consider the bonding between carbon (C) and sulfur (S). CS is a diatomic molecule and its molecular orbital diagram involves the […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-46529","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/46529","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=46529"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/46529\/revisions"}],"predecessor-version":[{"id":46534,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/46529\/revisions\/46534"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=46529"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=46529"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=46529"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
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