{"id":46282,"date":"2025-07-02T02:49:29","date_gmt":"2025-07-02T02:49:29","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=46282"},"modified":"2025-07-02T02:49:31","modified_gmt":"2025-07-02T02:49:31","slug":"write-the-formula-unit-for-the-ionic-compound-formed-when-the-tiniv-ion-and-the-sulfate-ion-react","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/write-the-formula-unit-for-the-ionic-compound-formed-when-the-tiniv-ion-and-the-sulfate-ion-react\/","title":{"rendered":"Write the formula unit for the ionic compound formed when the tin(IV) ion and the sulfate ion react."},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Write the formula unit for the ionic compound formed when the tin(IV) ion and the sulfate ion react. Sn(SO4)2<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"700\" height=\"328\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/image-68.png\" alt=\"\" class=\"wp-image-46283\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/image-68.png 700w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/image-68-300x141.png 300w\" sizes=\"auto, (max-width: 700px) 100vw, 700px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">The correct formula unit for the ionic compound formed between the tin(IV) ion and the sulfate ion is&nbsp;<strong>Sn(SO\u2084)\u2082<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">To determine the chemical formula for an ionic compound, we must balance the charges of the cation (the positive ion) and the anion (the negative ion) to form a neutral compound.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Identify the Cation and its Charge:<\/strong>\u00a0The cation is the tin(IV) ion. The name &#8220;tin(IV)&#8221; uses the Stock system, where the Roman numeral (IV) directly indicates the charge of the metal ion. Therefore, the tin(IV) ion has a charge of +4 and is written as\u00a0<strong>Sn\u2074\u207a<\/strong>.<\/li>\n\n\n\n<li><strong>Identify the Anion and its Charge:<\/strong>\u00a0The anion is the sulfate ion. Sulfate is a common polyatomic ion, which is a group of covalently bonded atoms with an overall charge. The chemical formula for the sulfate ion is SO\u2084, and it has a charge of -2. It is written as\u00a0<strong>SO\u2084\u00b2\u207b<\/strong>.<\/li>\n\n\n\n<li><strong>Balance the Charges:<\/strong>\u00a0The goal is to combine the Sn\u2074\u207a and SO\u2084\u00b2\u207b ions in a ratio that makes the total charge of the compound equal to zero. We need to find the least common multiple of the magnitudes of the charges (4 and 2), which is 4.\n<ul class=\"wp-block-list\">\n<li>To get a total positive charge of +4, we need one tin(IV) ion: 1 \u00d7 (+4) = +4.<\/li>\n\n\n\n<li>To get a total negative charge of -4, we need two sulfate ions: 2 \u00d7 (-2) = -4.<\/li>\n\n\n\n<li>The sum of the charges is (+4) + (-4) = 0, resulting in a neutral compound.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Write the Formula Unit:<\/strong>\u00a0The formula is written by combining the symbols for the ions and using subscripts to indicate the number of each ion needed. The cation (Sn) is written first, followed by the anion (SO\u2084).\n<ul class=\"wp-block-list\">\n<li>We need one Sn\u2074\u207a ion, so the subscript for Sn is 1 (which is omitted by convention).<\/li>\n\n\n\n<li>We need two SO\u2084\u00b2\u207b ions. When more than one polyatomic ion is required, its formula is enclosed in parentheses, and the number needed is written as a subscript outside the parentheses.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<p class=\"wp-block-paragraph\">Combining these parts gives the final formula:&nbsp;<strong>Sn(SO\u2084)\u2082<\/strong>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Based on the multiple-choice question in the image, the correctly derived formula, Sn(SO\u2084)\u2082, is not listed as an option. Therefore, the correct answer to select from the provided list would be\u00a0<strong>&#8220;none of these choices&#8221;<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner8-89.jpeg\" alt=\"\" class=\"wp-image-46284\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner8-89.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner8-89-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner8-89-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Write the formula unit for the ionic compound formed when the tin(IV) ion and the sulfate ion react. Sn(SO4)2 The Correct Answer and Explanation is: The correct formula unit for the ionic compound formed between the tin(IV) ion and the sulfate ion is&nbsp;Sn(SO\u2084)\u2082. Explanation: To determine the chemical formula for an ionic compound, we must [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-46282","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/46282","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=46282"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/46282\/revisions"}],"predecessor-version":[{"id":46285,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/46282\/revisions\/46285"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=46282"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=46282"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=46282"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}