{"id":46007,"date":"2025-07-01T17:23:02","date_gmt":"2025-07-01T17:23:02","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=46007"},"modified":"2025-07-01T17:23:06","modified_gmt":"2025-07-01T17:23:06","slug":"what-is-the-change-in-the-oxidation-number-of-manganese-in-the-following","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/what-is-the-change-in-the-oxidation-number-of-manganese-in-the-following\/","title":{"rendered":"What is the change in the oxidation number of manganese in the following"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">What is the change in the oxidation number of manganese in the following? KMnO4 \u2192 MnSO4 Increase by four units. Increase by three units. Decrease by four units. Decrease by five units<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">The correct answer is <strong>Decrease by five units<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">In the reaction <strong>KMnO4 \u2192 MnSO4<\/strong>, we need to track the change in the oxidation number of manganese (Mn) as it goes from one compound to another.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Oxidation state of Mn in KMnO4<\/strong>:\n<ul class=\"wp-block-list\">\n<li>Potassium permanganate (KMnO4) consists of the potassium ion (K\u207a), the permanganate ion (MnO\u2084\u207b), and the overall charge is neutral.<\/li>\n\n\n\n<li>In the permanganate ion, the sum of the oxidation states of all atoms is -1 (since it is an anion).<\/li>\n\n\n\n<li>Oxygen (O) typically has an oxidation state of -2. Since there are four oxygen atoms, the total oxidation state for oxygen is 4 \u00d7 (-2) = -8.<\/li>\n\n\n\n<li>To balance the -8 from oxygen, the oxidation state of manganese (Mn) must be +7 (because +7 + (-8) = -1). Therefore, the oxidation state of Mn in KMnO4 is +7.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Oxidation state of Mn in MnSO4<\/strong>:\n<ul class=\"wp-block-list\">\n<li>In manganese sulfate (MnSO4), sulfate (SO\u2084\u00b2\u207b) is the anion, and it carries a charge of -2. The compound is neutral, so the oxidation state of manganese must be +2 to balance the -2 charge from sulfate.<\/li>\n\n\n\n<li>Therefore, the oxidation state of Mn in MnSO4 is +2.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Change in the oxidation number of Mn<\/strong>:\n<ul class=\"wp-block-list\">\n<li>The oxidation number of manganese changes from +7 in KMnO4 to +2 in MnSO4.<\/li>\n\n\n\n<li>The change is calculated as: <strong>+2 (Mn in MnSO4) &#8211; (+7) (Mn in KMnO4) = -5<\/strong>.<\/li>\n\n\n\n<li>This indicates a decrease in the oxidation state by 5 units.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<p class=\"wp-block-paragraph\">Thus, the oxidation state of manganese decreases by five units in the given reaction, from +7 to +2. This is a reduction, which means manganese has gained electrons in the process.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner8-70.jpeg\" alt=\"\" class=\"wp-image-46008\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner8-70.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner8-70-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner8-70-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>What is the change in the oxidation number of manganese in the following? KMnO4 \u2192 MnSO4 Increase by four units. Increase by three units. Decrease by four units. Decrease by five units The Correct Answer and Explanation is: The correct answer is Decrease by five units. Explanation: In the reaction KMnO4 \u2192 MnSO4, we need [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-46007","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/46007","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=46007"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/46007\/revisions"}],"predecessor-version":[{"id":46009,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/46007\/revisions\/46009"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=46007"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=46007"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=46007"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}