{"id":45999,"date":"2025-07-01T17:09:19","date_gmt":"2025-07-01T17:09:19","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=45999"},"modified":"2025-07-01T17:09:27","modified_gmt":"2025-07-01T17:09:27","slug":"calculate-the-theoretical-yield-of-cyclohexanone-from-16-ml-of-cyclohexanol","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/calculate-the-theoretical-yield-of-cyclohexanone-from-16-ml-of-cyclohexanol\/","title":{"rendered":"calculate the theoretical yield of cyclohexanone from 16 ml of cyclohexanol."},"content":{"rendered":"\n

calculate the theoretical yield of cyclohexanone from 16 ml of cyclohexanol. molecular weight of cyclohexanol = 100.26 g, molecular weight of cyclohexanone = 98.14 g, and the density of cyclohexanol = 0.96 g\/ml<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

To calculate the theoretical yield of cyclohexanone from 16 mL of cyclohexanol, we first need to follow these steps:<\/p>\n\n\n\n

Step 1: Calculate the mass of cyclohexanol<\/h3>\n\n\n\n

The density of cyclohexanol is 0.96 g\/mL. Therefore, the mass of 16 mL of cyclohexanol is:Mass of cyclohexanol=Density\u00d7Volume\\text{Mass of cyclohexanol} = \\text{Density} \\times \\text{Volume}Mass of cyclohexanol=Density\u00d7VolumeMass of cyclohexanol=0.96\u2009g\/mL\u00d716\u2009mL=15.36\u2009g\\text{Mass of cyclohexanol} = 0.96 \\, \\text{g\/mL} \\times 16 \\, \\text{mL} = 15.36 \\, \\text{g}Mass of cyclohexanol=0.96g\/mL\u00d716mL=15.36g<\/p>\n\n\n\n

Step 2: Convert the mass of cyclohexanol to moles<\/h3>\n\n\n\n

The molecular weight of cyclohexanol is 100.26 g\/mol. To convert the mass to moles, use the formula:Moles of cyclohexanol=Mass of cyclohexanolMolecular weight of cyclohexanol\\text{Moles of cyclohexanol} = \\frac{\\text{Mass of cyclohexanol}}{\\text{Molecular weight of cyclohexanol}}Moles of cyclohexanol=Molecular weight of cyclohexanolMass of cyclohexanol\u200bMoles of cyclohexanol=15.36\u2009g100.26\u2009g\/mol=0.1534\u2009mol\\text{Moles of cyclohexanol} = \\frac{15.36 \\, \\text{g}}{100.26 \\, \\text{g\/mol}} = 0.1534 \\, \\text{mol}Moles of cyclohexanol=100.26g\/mol15.36g\u200b=0.1534mol<\/p>\n\n\n\n

Step 3: Determine the moles of cyclohexanone formed<\/h3>\n\n\n\n

In this reaction, cyclohexanol undergoes a dehydration process (typically catalytic dehydrogenation) to form cyclohexanone. Assuming a 100% conversion rate and a 1:1 molar ratio between cyclohexanol and cyclohexanone, the moles of cyclohexanone produced will be the same as the moles of cyclohexanol.Moles of cyclohexanone=0.1534\u2009mol\\text{Moles of cyclohexanone} = 0.1534 \\, \\text{mol}Moles of cyclohexanone=0.1534mol<\/p>\n\n\n\n

Step 4: Convert moles of cyclohexanone to mass<\/h3>\n\n\n\n

Now that we know the moles of cyclohexanone, we can calculate its mass. The molecular weight of cyclohexanone is 98.14 g\/mol. Use the following formula:Mass of cyclohexanone=Moles of cyclohexanone\u00d7Molecular weight of cyclohexanone\\text{Mass of cyclohexanone} = \\text{Moles of cyclohexanone} \\times \\text{Molecular weight of cyclohexanone}Mass of cyclohexanone=Moles of cyclohexanone\u00d7Molecular weight of cyclohexanoneMass of cyclohexanone=0.1534\u2009mol\u00d798.14\u2009g\/mol=15.04\u2009g\\text{Mass of cyclohexanone} = 0.1534 \\, \\text{mol} \\times 98.14 \\, \\text{g\/mol} = 15.04 \\, \\text{g}Mass of cyclohexanone=0.1534mol\u00d798.14g\/mol=15.04g<\/p>\n\n\n\n

Step 5: Conclusion<\/h3>\n\n\n\n

Thus, the theoretical yield of cyclohexanone from 16 mL of cyclohexanol is 15.04 g, assuming complete conversion of cyclohexanol to cyclohexanone with no side reactions.<\/p>\n\n\n\n

\"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

calculate the theoretical yield of cyclohexanone from 16 ml of cyclohexanol. molecular weight of cyclohexanol = 100.26 g, molecular weight of cyclohexanone = 98.14 g, and the density of cyclohexanol = 0.96 g\/ml The Correct Answer and Explanation is: To calculate the theoretical yield of cyclohexanone from 16 mL of cyclohexanol, we first need to […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-45999","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/45999","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=45999"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/45999\/revisions"}],"predecessor-version":[{"id":46001,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/45999\/revisions\/46001"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=45999"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=45999"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=45999"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}