{"id":45950,"date":"2025-07-01T15:23:43","date_gmt":"2025-07-01T15:23:43","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=45950"},"modified":"2025-07-01T15:23:44","modified_gmt":"2025-07-01T15:23:44","slug":"how-much-potential-difference-is-needed-to-charge-a-6-8-microfarad-capacitor-to-have-56-microcoulombs-across-its-plates","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/how-much-potential-difference-is-needed-to-charge-a-6-8-microfarad-capacitor-to-have-56-microcoulombs-across-its-plates\/","title":{"rendered":"How much potential difference is needed to charge a 6.8 microFarad capacitor to have 56 microCoulombs across its plates"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">How much potential difference is needed to charge a 6.8 microFarad capacitor to have 56 microCoulombs across its plates? Select one: a. 9 volts b. 8.24 volts c. 6.8 volts d. 5.6 volts<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"700\" height=\"203\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/image-42.png\" alt=\"\" class=\"wp-image-45951\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/image-42.png 700w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/image-42-300x87.png 300w\" sizes=\"auto, (max-width: 700px) 100vw, 700px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">To determine the potential difference (voltage) needed to charge the capacitor, we can use the formula for capacitance:Q=C\u00d7VQ = C \\times VQ=C\u00d7V<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Where:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>QQQ is the charge in coulombs,<\/li>\n\n\n\n<li>CCC is the capacitance in farads,<\/li>\n\n\n\n<li>VVV is the potential difference (voltage) in volts.<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">In this problem:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The charge Q=56\u2009\u03bcC=56\u00d710\u22126\u2009CQ = 56 \\, \\mu C = 56 \\times 10^{-6} \\, CQ=56\u03bcC=56\u00d710\u22126C,<\/li>\n\n\n\n<li>The capacitance C=6.8\u2009\u03bcF=6.8\u00d710\u22126\u2009FC = 6.8 \\, \\mu F = 6.8 \\times 10^{-6} \\, FC=6.8\u03bcF=6.8\u00d710\u22126F.<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">We need to find the voltage VVV, so rearranging the formula:V=QCV = \\frac{Q}{C}V=CQ\u200b<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Substitute the known values:V=56\u00d710\u221266.8\u00d710\u22126=566.8=8.24\u2009volts.V = \\frac{56 \\times 10^{-6}}{6.8 \\times 10^{-6}} = \\frac{56}{6.8} = 8.24 \\, \\text{volts}.V=6.8\u00d710\u2212656\u00d710\u22126\u200b=6.856\u200b=8.24volts.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Thus, the correct answer is <strong>b. 8.24 volts<\/strong>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">This result is derived from the relationship between charge, capacitance, and voltage. Since the capacitance is constant, a larger charge requires a higher potential difference, and this equation directly gives us the necessary voltage to achieve the specified charge on the capacitor.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner8-57.jpeg\" alt=\"\" class=\"wp-image-45952\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner8-57.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner8-57-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner8-57-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>How much potential difference is needed to charge a 6.8 microFarad capacitor to have 56 microCoulombs across its plates? Select one: a. 9 volts b. 8.24 volts c. 6.8 volts d. 5.6 volts The Correct Answer and Explanation is: To determine the potential difference (voltage) needed to charge the capacitor, we can use the formula [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-45950","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/45950","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=45950"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/45950\/revisions"}],"predecessor-version":[{"id":45953,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/45950\/revisions\/45953"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=45950"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=45950"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=45950"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}