{"id":45910,"date":"2025-07-01T14:20:33","date_gmt":"2025-07-01T14:20:33","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=45910"},"modified":"2025-07-01T14:20:35","modified_gmt":"2025-07-01T14:20:35","slug":"which-equation-represents-the-graph-given-below","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/which-equation-represents-the-graph-given-below\/","title":{"rendered":"Which equation represents the graph given below"},"content":{"rendered":"\n

Which equation represents the graph given below? Select one: a. 5y – 2x = -1 b. 3y + 2x = 1 c. 5y + 2x = -1 d. 2x – 5y = -1 How should you graph the equation y = 8x – 7 using the slope-intercept form? Select one: a. Plot a point at 7 on the y-intercept. Then travel up 8 units and to the right 1 unit and plot another point. Connect the points to create a line. b. Plot a point at -7 on the x-intercept. Then travel up 1 unit and to the right 8 units and plot another point. Connect the points to create a line. c. Plot a point at 8 on the y-intercept. Then travel down 7 units and to the right 1 unit and plot another point. Connect the points to create a line<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

Correct Answers:<\/strong><\/p>\n\n\n\n

First question:<\/strong> c. 5y + 2x = -1
Second question:<\/strong> a. Plot a point at -7 on the y-intercept. Then travel up 8 units and to the right 1 unit and plot another point. Connect the points to create a line.<\/p>\n\n\n\n

\n\n\n\n

Explanation<\/strong><\/h3>\n\n\n\n

Finding the Equation from the Graph<\/strong><\/p>\n\n\n\n

To determine which equation represents the graphed line, we first need to find the line’s slope (m) and y-intercept (b). We can find the slope by identifying two distinct points on the line and using the formula m = (y2 – y1) \/ (x2 – x1).<\/p>\n\n\n\n

By examining the graph, we can clearly identify two points where the line crosses the grid intersections: (-3, 1) and (2, -1).<\/p>\n\n\n\n

Using these points, we calculate the slope:
m = (-1 – 1) \/ (2 – (-3)) = -2 \/ (2 + 3) = -2\/5.<\/p>\n\n\n\n

Now that we have the slope (m = -2\/5), we can use one of the points (let’s use (2, -1)) and the slope-intercept form (y = mx + b) to find the y-intercept (b).
-1 = (-2\/5)(2) + b
-1 = -4\/5 + b
b = -1 + 4\/5 = -1\/5.<\/p>\n\n\n\n

The equation of the line is y = (-2\/5)x – 1\/5. To match this with the given options, we convert it to standard form. First, multiply the entire equation by 5 to eliminate the fractions:
5y = -2x – 1
Then, add 2x to both sides:
2x + 5y = -1. This matches option c. 5y + 2x = -1<\/strong>.<\/p>\n\n\n\n

Graphing Using Slope-Intercept Form<\/strong><\/p>\n\n\n\n

The second question asks how to graph the equation y = 8x – 7. This equation is already in the slope-intercept form, y = mx + b.<\/p>\n\n\n\n

Here, the slope (m) is 8, and the y-intercept (b) is -7.<\/p>\n\n\n\n

The process to graph this is as follows:<\/p>\n\n\n\n

    \n
  1. Plot the y-intercept:<\/strong>\u00a0The y-intercept is the point where the line crosses the y-axis. In this case, b = -7, so our first point is at (0, -7).<\/li>\n\n\n\n
  2. Use the slope to find a second point:<\/strong>\u00a0The slope, m = 8, can be written as a fraction, 8\/1. This represents the “rise over run”. From the y-intercept point (0, -7), we “rise” 8 units (move up 8 units) and “run” 1 unit (move to the right 1 unit). This brings us to a second point at (1, 1).<\/li>\n\n\n\n
  3. Draw the line:<\/strong>\u00a0Connect the two points, (0, -7) and (1, 1), with a straight line.<\/li>\n<\/ol>\n\n\n\n

    This procedure is described perfectly in option a<\/strong>.thumb_upthumb_down<\/p>\n\n\n\n

    \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

    Which equation represents the graph given below? Select one: a. 5y – 2x = -1 b. 3y + 2x = 1 c. 5y + 2x = -1 d. 2x – 5y = -1 How should you graph the equation y = 8x – 7 using the slope-intercept form? Select one: a. Plot a point at […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-45910","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/45910","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=45910"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/45910\/revisions"}],"predecessor-version":[{"id":45913,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/45910\/revisions\/45913"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=45910"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=45910"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=45910"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}