{"id":45824,"date":"2025-07-01T12:29:16","date_gmt":"2025-07-01T12:29:16","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=45824"},"modified":"2025-07-01T12:29:18","modified_gmt":"2025-07-01T12:29:18","slug":"mass-of-unknown-transferred-mass-of-filter-paper-mass-of-paper-and-dry-baso","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/mass-of-unknown-transferred-mass-of-filter-paper-mass-of-paper-and-dry-baso\/","title":{"rendered":"Mass of unknown transferred Mass of filter paper Mass of paper and dry BaSO"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Mass of unknown transferred Mass of filter paper Mass of paper and dry BaSO, Trial 1 (Yours) 0.294g 0.907g 1.203g Trial 2 (Partners) 0.253g 0.899g 1.163g Give me the Calculations week 1 Mass of dry BasO Calculated percent sulfate in unknown AVERAGE PERCENT SULFATE<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">To calculate the mass of dry BaSO\u2084 (barium sulfate) and the percentage of sulfate in the unknown sample, we need to follow a step-by-step process using the data provided from both trials.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Calculate the mass of BaSO\u2084 in each trial.<\/h3>\n\n\n\n<h4 class=\"wp-block-heading\">Trial 1 (Your Sample):<\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Mass of paper and dry BaSO\u2084: 1.203 g<\/li>\n\n\n\n<li>Mass of filter paper: 0.907 g<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Mass of dry BaSO\u2084 = Mass of paper and dry BaSO\u2084 &#8211; Mass of filter paper<br>Mass of dry BaSO\u2084 = 1.203 g &#8211; 0.907 g = <strong>0.296 g<\/strong><\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Trial 2 (Partner&#8217;s Sample):<\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Mass of paper and dry BaSO\u2084: 1.163 g<\/li>\n\n\n\n<li>Mass of filter paper: 0.899 g<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Mass of dry BaSO\u2084 = Mass of paper and dry BaSO\u2084 &#8211; Mass of filter paper<br>Mass of dry BaSO\u2084 = 1.163 g &#8211; 0.899 g = <strong>0.264 g<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Calculate the percent sulfate in the unknown sample for each trial.<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">To calculate the percent sulfate in the unknown, we first need to know the molar masses:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>BaSO\u2084 (barium sulfate):<br>Ba = 137.33 g\/mol, S = 32.07 g\/mol, O = 16.00 g\/mol<br>Molar mass of BaSO\u2084 = 137.33 + 32.07 + (4 \u00d7 16.00) = <strong>233.39 g\/mol<\/strong><\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">The percentage of sulfate (SO\u2084) in BaSO\u2084 is calculated as the mass of SO\u2084 divided by the mass of BaSO\u2084, multiplied by 100.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Molar mass of SO\u2084 = 32.07 + (4 \u00d7 16.00) = <strong>96.07 g\/mol<\/strong><\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">So, the percent sulfate in BaSO\u2084 is:96.07233.39\u00d7100=41.16%\\frac{{96.07}}{{233.39}} \\times 100 = 41.16\\%233.3996.07\u200b\u00d7100=41.16%<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Now we can calculate the percent sulfate in the unknown sample for each trial.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Trial 1:<\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Mass of dry BaSO\u2084 = 0.296 g<\/li>\n\n\n\n<li>Percent sulfate in BaSO\u2084 = 41.16%<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Percent sulfate in unknown = 0.296\u2009g\u00d741.16100=0.121\u2009g0.296 \\, \\text{g} \\times \\frac{{41.16}}{{100}} = 0.121 \\, \\text{g}0.296g\u00d710041.16\u200b=0.121g<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Percent sulfate in unknown sample = <strong>12.1%<\/strong><\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Trial 2:<\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Mass of dry BaSO\u2084 = 0.264 g<\/li>\n\n\n\n<li>Percent sulfate in BaSO\u2084 = 41.16%<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Percent sulfate in unknown = 0.264\u2009g\u00d741.16100=0.109\u2009g0.264 \\, \\text{g} \\times \\frac{{41.16}}{{100}} = 0.109 \\, \\text{g}0.264g\u00d710041.16\u200b=0.109g<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Percent sulfate in unknown sample = <strong>10.9%<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Calculate the average percent sulfate in the unknown.<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Average&nbsp;percent&nbsp;sulfate=12.1%+10.9%2=11.5%\\text{Average percent sulfate} = \\frac{{12.1\\% + 10.9\\%}}{2} = 11.5\\%Average&nbsp;percent&nbsp;sulfate=212.1%+10.9%\u200b=11.5%<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Final Results:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Mass of dry BaSO\u2084 (Trial 1):<\/strong> 0.296 g<\/li>\n\n\n\n<li><strong>Mass of dry BaSO\u2084 (Trial 2):<\/strong> 0.264 g<\/li>\n\n\n\n<li><strong>Percent sulfate in unknown (Trial 1):<\/strong> 12.1%<\/li>\n\n\n\n<li><strong>Percent sulfate in unknown (Trial 2):<\/strong> 10.9%<\/li>\n\n\n\n<li><strong>Average percent sulfate in unknown:<\/strong> <strong>11.5%<\/strong><\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">This calculation shows the concentration of sulfate in the unknown sample based on the barium sulfate precipitate formed during the experiment. The average value gives a reliable estimate of the sulfate content across both trials.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner8-31.jpeg\" alt=\"\" class=\"wp-image-45825\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner8-31.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner8-31-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/07\/learnexams-banner8-31-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Mass of unknown transferred Mass of filter paper Mass of paper and dry BaSO, Trial 1 (Yours) 0.294g 0.907g 1.203g Trial 2 (Partners) 0.253g 0.899g 1.163g Give me the Calculations week 1 Mass of dry BasO Calculated percent sulfate in unknown AVERAGE PERCENT SULFATE The Correct Answer and Explanation is: To calculate the mass of [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-45824","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/45824","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=45824"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/45824\/revisions"}],"predecessor-version":[{"id":45826,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/45824\/revisions\/45826"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=45824"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=45824"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=45824"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}