What is the oxidation state of each element in SO4(2-)?<\/p>\n\n\n\n
The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n To determine the oxidation state of each element in the sulfate ion (SO\u2084\u00b2\u207b), follow these steps:<\/p>\n\n\n\n The sulfate ion has a 2- charge, written as SO\u2084\u00b2\u207b. This means the total oxidation states of all the elements in the ion must sum up to -2.<\/p>\n\n\n\n In most compounds, oxygen has an oxidation state of -2. Since there are four oxygen atoms in the sulfate ion, the total oxidation state of all oxygen atoms combined will be: 4\u00d7(\u22122)=\u221284 \\times (-2) = -8<\/p>\n\n\n\n Let the oxidation state of sulfur be xx. Since the sum of the oxidation states of all elements must equal the charge of the ion (-2), we can set up the following equation: x+(\u22128)=\u22122x + (-8) = -2<\/p>\n\n\n\n Solving for xx, we get: x=+6x = +6<\/p>\n\n\n\n To ensure the calculation is correct, add up the oxidation states of sulfur and oxygen:<\/p>\n\n\n\n The sum of the oxidation states is: +6+(\u22128)=\u22122+6 + (-8) = -2<\/p>\n\n\n\n This matches the overall charge of the sulfate ion, confirming that the oxidation state of sulfur is +6 and the oxidation state of oxygen is -2.<\/p>\n\n\n\n In the sulfate ion (SO\u2084\u00b2\u207b):<\/p>\n\n\n\n This method of assigning oxidation states ensures that the overall charge of the ion is accurately accounted for.<\/p>\n","protected":false},"excerpt":{"rendered":" What is the oxidation state of each element in SO4(2-)? The correct answer and explanation is: To determine the oxidation state of each element in the sulfate ion (SO\u2084\u00b2\u207b), follow these steps: Step 1: Understand the charge of the ion The sulfate ion has a 2- charge, written as SO\u2084\u00b2\u207b. This means the total oxidation […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-43526","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/43526","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=43526"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/43526\/revisions"}],"predecessor-version":[{"id":43527,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/43526\/revisions\/43527"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=43526"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=43526"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=43526"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Step 1: Understand the charge of the ion<\/h3>\n\n\n\n
Step 2: Assign oxidation states to oxygen<\/h3>\n\n\n\n
Step 3: Assign the oxidation state to sulfur<\/h3>\n\n\n\n
Step 4: Double-check the result<\/h3>\n\n\n\n
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Conclusion:<\/h3>\n\n\n\n
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