{"id":43414,"date":"2025-06-30T05:41:32","date_gmt":"2025-06-30T05:41:32","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=43414"},"modified":"2025-06-30T05:41:33","modified_gmt":"2025-06-30T05:41:33","slug":"what-is-the-oxidation-number-of-s-in-so42","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/what-is-the-oxidation-number-of-s-in-so42\/","title":{"rendered":"What is the oxidation number of S in SO42-"},"content":{"rendered":"\n<p>What is the oxidation number of S in SO42-?<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The oxidation number of sulfur (S) in the sulfate ion (SO\u2084\u00b2\u207b) is +6.<\/p>\n\n\n\n<p>To determine this, we need to use the rules for assigning oxidation states:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Oxidation state of oxygen<\/strong>: Oxygen in most compounds, including sulfates, has an oxidation state of -2.<\/li>\n\n\n\n<li><strong>Total charge of the ion<\/strong>: The sulfate ion, SO\u2084\u00b2\u207b, has a charge of -2. The sum of the oxidation numbers in this ion must equal -2.<\/li>\n\n\n\n<li><strong>Assigning the oxidation state of sulfur<\/strong>: Let the oxidation number of sulfur be xx. Since there are four oxygen atoms, each with an oxidation state of -2, the total contribution from oxygen is 4\u00d7(\u22122)=\u221284 \\times (-2) = -8. The sum of the oxidation numbers must equal the overall charge of the ion, which is -2. Therefore, the equation is: x+(\u22128)=\u22122x + (-8) = -2 Simplifying this equation: x\u22128=\u22122x &#8211; 8 = -2 Solving for xx: x=+6x = +6<\/li>\n<\/ol>\n\n\n\n<p>Thus, the oxidation number of sulfur in SO\u2084\u00b2\u207b is +6.<\/p>\n\n\n\n<p>This is consistent with sulfur&#8217;s behavior in various compounds, where it often has oxidation states ranging from +2 to +6. In the case of the sulfate ion, sulfur achieves its highest common oxidation state, +6, as it forms bonds with the oxygen atoms that contribute to the overall negative charge of the ion.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>What is the oxidation number of S in SO42-? The correct answer and explanation is: The oxidation number of sulfur (S) in the sulfate ion (SO\u2084\u00b2\u207b) is +6. To determine this, we need to use the rules for assigning oxidation states: Thus, the oxidation number of sulfur in SO\u2084\u00b2\u207b is +6. This is consistent with [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-43414","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/43414","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=43414"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/43414\/revisions"}],"predecessor-version":[{"id":43415,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/43414\/revisions\/43415"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=43414"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=43414"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=43414"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}