{"id":43387,"date":"2025-06-29T19:18:22","date_gmt":"2025-06-29T19:18:22","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=43387"},"modified":"2025-06-29T19:18:24","modified_gmt":"2025-06-29T19:18:24","slug":"calculate-the-mass-of-sodium-phosphate-dodecahydrate-you-will-need-to-prepare-250-ml-of-0-20-m-aqueous-sodium-phosphate-solution","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/calculate-the-mass-of-sodium-phosphate-dodecahydrate-you-will-need-to-prepare-250-ml-of-0-20-m-aqueous-sodium-phosphate-solution\/","title":{"rendered":"Calculate the mass of sodium phosphate dodecahydrate you will need to prepare 250 mL of 0.20 M aqueous sodium phosphate solution."},"content":{"rendered":"\n<p>Calculate the mass of sodium phosphate dodecahydrate you will need to prepare 250 mL of 0.20 M aqueous sodium phosphate solution.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To calculate the mass of sodium phosphate dodecahydrate (Na\u2083PO\u2084\u00b712H\u2082O) needed to prepare a 250 mL (0.250 L) solution with a concentration of 0.20 M, we can follow these steps:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Write down the given information<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Desired concentration of sodium phosphate solution: 0.20 M<\/li>\n\n\n\n<li>Volume of solution to prepare: 250 mL = 0.250 L<\/li>\n\n\n\n<li>Molar mass of sodium phosphate dodecahydrate (Na\u2083PO\u2084\u00b712H\u2082O)<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Find the moles of sodium phosphate needed<\/h3>\n\n\n\n<p>The formula for calculating moles from concentration and volume is: Moles&nbsp;of&nbsp;Na\u2083PO\u2084\\cdotp12H\u2082O=Molarity\u00d7Volume&nbsp;in&nbsp;Liters\\text{Moles of Na\u2083PO\u2084\u00b712H\u2082O} = \\text{Molarity} \\times \\text{Volume in Liters}Moles&nbsp;of&nbsp;Na\u2083PO\u2084\\cdotp12H\u2082O=Molarity\u00d7Volume&nbsp;in&nbsp;Liters Moles&nbsp;of&nbsp;Na\u2083PO\u2084\\cdotp12H\u2082O=0.20\u2009mol\/L\u00d70.250\u2009L\\text{Moles of Na\u2083PO\u2084\u00b712H\u2082O} = 0.20 \\, \\text{mol\/L} \\times 0.250 \\, \\text{L}Moles&nbsp;of&nbsp;Na\u2083PO\u2084\\cdotp12H\u2082O=0.20mol\/L\u00d70.250L Moles&nbsp;of&nbsp;Na\u2083PO\u2084\\cdotp12H\u2082O=0.050\u2009mol\\text{Moles of Na\u2083PO\u2084\u00b712H\u2082O} = 0.050 \\, \\text{mol}Moles&nbsp;of&nbsp;Na\u2083PO\u2084\\cdotp12H\u2082O=0.050mol<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Calculate the molar mass of sodium phosphate dodecahydrate<\/h3>\n\n\n\n<p>Sodium phosphate dodecahydrate (Na\u2083PO\u2084\u00b712H\u2082O) consists of:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>3 sodium (Na) atoms = 3 \u00d7 22.99 = 68.97 g\/mol<\/li>\n\n\n\n<li>1 phosphate (PO\u2084) group = 1 \u00d7 (30.97 + 4 \u00d7 16.00) = 94.97 g\/mol<\/li>\n\n\n\n<li>12 water (H\u2082O) molecules = 12 \u00d7 (2 \u00d7 1.008 + 16.00) = 216.24 g\/mol<\/li>\n<\/ul>\n\n\n\n<p>Adding these up: Molar&nbsp;mass&nbsp;of&nbsp;Na\u2083PO\u2084\\cdotp12H\u2082O=68.97+94.97+216.24=380.18\u2009g\/mol\\text{Molar mass of Na\u2083PO\u2084\u00b712H\u2082O} = 68.97 + 94.97 + 216.24 = 380.18 \\, \\text{g\/mol}Molar&nbsp;mass&nbsp;of&nbsp;Na\u2083PO\u2084\\cdotp12H\u2082O=68.97+94.97+216.24=380.18g\/mol<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 4: Calculate the mass of sodium phosphate dodecahydrate<\/h3>\n\n\n\n<p>To find the mass of sodium phosphate dodecahydrate needed, use the formula: Mass=Moles\u00d7Molar&nbsp;mass\\text{Mass} = \\text{Moles} \\times \\text{Molar mass}Mass=Moles\u00d7Molar&nbsp;mass Mass=0.050\u2009mol\u00d7380.18\u2009g\/mol\\text{Mass} = 0.050 \\, \\text{mol} \\times 380.18 \\, \\text{g\/mol}Mass=0.050mol\u00d7380.18g\/mol Mass=19.01\u2009g\\text{Mass} = 19.01 \\, \\text{g}Mass=19.01g<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion:<\/h3>\n\n\n\n<p>You will need <strong>19.01 grams<\/strong> of sodium phosphate dodecahydrate to prepare 250 mL of a 0.20 M aqueous sodium phosphate solution.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-485.jpeg\" alt=\"\" class=\"wp-image-43388\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-485.jpeg 1024w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-485-300x300.jpeg 300w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-485-150x150.jpeg 150w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-485-768x768.jpeg 768w\" sizes=\"auto, (max-width: 1024px) 100vw, 1024px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Calculate the mass of sodium phosphate dodecahydrate you will need to prepare 250 mL of 0.20 M aqueous sodium phosphate solution. The Correct Answer and Explanation is: To calculate the mass of sodium phosphate dodecahydrate (Na\u2083PO\u2084\u00b712H\u2082O) needed to prepare a 250 mL (0.250 L) solution with a concentration of 0.20 M, we can follow these [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-43387","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/43387","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=43387"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/43387\/revisions"}],"predecessor-version":[{"id":43389,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/43387\/revisions\/43389"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=43387"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=43387"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=43387"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}