{"id":43379,"date":"2025-06-29T19:09:51","date_gmt":"2025-06-29T19:09:51","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=43379"},"modified":"2025-06-29T19:09:52","modified_gmt":"2025-06-29T19:09:52","slug":"extra-practice-in-exercises-1-6-solve-the-literal-equation-for-y","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/extra-practice-in-exercises-1-6-solve-the-literal-equation-for-y\/","title":{"rendered":"Extra Practice In Exercises 1-6, solve the literal equation for y."},"content":{"rendered":"\n
\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

Of course. Here are the correct answers for the visible math problems, followed by an explanation of the methods used to solve them.<\/p>\n\n\n\n

Correct Answers<\/strong><\/h3>\n\n\n\n

Exercises 1\u20136: Solve for y<\/strong><\/p>\n\n\n\n

    \n
  1. y = 2x + 15<\/strong><\/li>\n\n\n\n
  2. y = 2 – 4x<\/strong><\/li>\n\n\n\n
  3. y = x – 2<\/strong><\/li>\n\n\n\n
  4. y = 11 – x<\/strong><\/li>\n\n\n\n
  5. y = 3x + 4<\/strong><\/li>\n\n\n\n
  6. y = (3x – 6) \/ -4<\/strong>\u00a0or\u00a0y = (6 – 3x) \/ 4<\/strong><\/li>\n<\/ol>\n\n\n\n

    Exercises 7\u201312: Solve for x<\/strong>
    7. x = y \/ 6<\/strong>
    8. x = q \/ (3 + 9z)<\/strong>
    9. x = (r – 4) \/ (7 – s)<\/strong>
    10. x = (y + 6) \/ 6<\/strong>
    11. x = (4g – r) \/ -2<\/strong> or x = (r – 4g) \/ 2<\/strong>
    12. x = (4z – 4) \/ 3<\/strong><\/p>\n\n\n\n

    Explanation<\/strong><\/h3>\n\n\n\n

    Solving a literal equation means isolating one specific variable in an equation that contains multiple variables. The process uses the same fundamental principles as solving a standard one-variable equation. The goal is to perform inverse operations to move all other terms to the opposite side of the equal sign, leaving the desired variable by itself.<\/p>\n\n\n\n

    For the first set of exercises, the goal was to solve for y<\/strong>. In problems like number 1 (y – 2x = 15), you isolate y by performing the opposite operation. Since 2x is being subtracted from y, you add 2x to both sides, resulting in y = 2x + 15. For problem 5 (3x – y = -4), you first subtract 3x from both sides to get -y = -4 – 3x. Because the y is negative, you must then multiply or divide the entire equation by -1 to find the value of positive y, which gives you y = 4 + 3x.<\/p>\n\n\n\n

    The second set of exercises required solving for x<\/strong>. These problems introduce a key step for when the variable appears in multiple terms. In problem 7 (y = 10x – 4x), you must first combine the like terms on the right side to get y = 6x before dividing by 6. For a problem like number 8 (q = 3x + 9xz), you cannot simply combine the terms. Instead, you must factor the x out of both terms, which gives you q = x(3 + 9z). From there, you can isolate x by dividing both sides by the entire expression in the parentheses. This factoring technique is essential for isolating a variable that is present in multiple, unlike terms. The final answer is an expression containing other variables, not a single number.thumb_upthumb_down<\/p>\n\n\n\n

    \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

    The Correct Answer and Explanation is: Of course. Here are the correct answers for the visible math problems, followed by an explanation of the methods used to solve them. Correct Answers Exercises 1\u20136: Solve for y Exercises 7\u201312: Solve for x7. x = y \/ 68. x = q \/ (3 + 9z)9. x = (r – 4) […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-43379","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/43379","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=43379"}],"version-history":[{"count":2,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/43379\/revisions"}],"predecessor-version":[{"id":43383,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/43379\/revisions\/43383"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=43379"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=43379"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=43379"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}