{"id":43244,"date":"2025-06-29T16:34:28","date_gmt":"2025-06-29T16:34:28","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=43244"},"modified":"2025-06-29T16:34:29","modified_gmt":"2025-06-29T16:34:29","slug":"phet-collision-lab-directions-go-to-the-website-http-phet-colorado-edu-en-simulation-collision-lab","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/phet-collision-lab-directions-go-to-the-website-http-phet-colorado-edu-en-simulation-collision-lab\/","title":{"rendered":"PhET Collision Lab Directions: Go to the website http:\/\/phet.colorado.edu\/en\/simulation\/collision-lab"},"content":{"rendered":"\n<p>PhET Collision Lab Directions: Go to the website http:\/\/phet.colorado.edu\/en\/simulation\/collision-lab Make sure you will check \\&#8221;Advanced\\&#8221; and from there the 1-dimension box is checked. For the first simulation two masses must be equal. Right after the two ball collide stop the play. Momenta Scenario #1: Elastic collision between balls of equal mass Make a hypothesis about initial and final momentums before playing with the sim. Hypothesis Item #<\/p>\n\n\n\n<p>Initial\/Before<\/p>\n\n\n\n<h1 class=\"wp-block-heading\">(Kg) (m\/s) (kg.m\/s) (kg) (m\/s) (kg.m\/s) Ball 1 1.5 1 1.5 Ball 2 1.5 .50 .75 Net Momentum<\/h1>\n\n\n\n<p>Final\/After<\/p>\n\n\n\n<p>(kg) (m\/s) (kg.m\/s) Make a datatable for the following: mass, velocity andmomentum of each ball based on the actual results Actual Item #<\/p>\n\n\n\n<p>Initial\/Before<br>(Kg) (m\/s) (kg.m\/s) (kg) Ball 1 Ball 2 Net Momentum<br>= Final\/After What is the relationship between the initial and final total-Net momentums<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"539\" height=\"671\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/image-523.png\" alt=\"\" class=\"wp-image-43245\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/image-523.png 539w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/image-523-241x300.png 241w\" sizes=\"auto, (max-width: 539px) 100vw, 539px\" \/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Hypothesis<\/strong>:\n<ul class=\"wp-block-list\">\n<li>Initially, before the collision, Ball 1 has momentum P=m\u00d7vP = m \\times vP=m\u00d7v. With the given mass and velocity for Ball 1, the momentum is: P1=1.5\u2009kg\u00d71\u2009m\/s=1.5\u2009kg.m\/sP_1 = 1.5 \\, \\text{kg} \\times 1 \\, \\text{m\/s} = 1.5 \\, \\text{kg.m\/s}P1\u200b=1.5kg\u00d71m\/s=1.5kg.m\/s For Ball 2, its initial momentum is: P2=1.5\u2009kg\u00d70.50\u2009m\/s=0.75\u2009kg.m\/sP_2 = 1.5 \\, \\text{kg} \\times 0.50 \\, \\text{m\/s} = 0.75 \\, \\text{kg.m\/s}P2\u200b=1.5kg\u00d70.50m\/s=0.75kg.m\/s Therefore, the <strong>Net Momentum<\/strong> before the collision is the sum of the momenta of both balls: Net\u00a0Momentum=1.5\u2009kg.m\/s+0.75\u2009kg.m\/s=2.25\u2009kg.m\/s\\text{Net Momentum} = 1.5 \\, \\text{kg.m\/s} + 0.75 \\, \\text{kg.m\/s} = 2.25 \\, \\text{kg.m\/s}Net\u00a0Momentum=1.5kg.m\/s+0.75kg.m\/s=2.25kg.m\/s<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Actual Results (after the collision)<\/strong>:\n<ul class=\"wp-block-list\">\n<li>After the collision, you&#8217;ll need to observe the new velocities of Ball 1 and Ball 2 from the simulation. Let\u2019s assume Ball 1&#8217;s velocity changes to 0.5\u2009m\/s0.5 \\, \\text{m\/s}0.5m\/s and Ball 2&#8217;s changes to 1.0\u2009m\/s1.0 \\, \\text{m\/s}1.0m\/s.<\/li>\n\n\n\n<li>The new momenta will be: P1\u2032=1.5\u2009kg\u00d70.5\u2009m\/s=0.75\u2009kg.m\/sP_1&#8242; = 1.5 \\, \\text{kg} \\times 0.5 \\, \\text{m\/s} = 0.75 \\, \\text{kg.m\/s}P1\u2032\u200b=1.5kg\u00d70.5m\/s=0.75kg.m\/s P2\u2032=1.5\u2009kg\u00d71.0\u2009m\/s=1.5\u2009kg.m\/sP_2&#8242; = 1.5 \\, \\text{kg} \\times 1.0 \\, \\text{m\/s} = 1.5 \\, \\text{kg.m\/s}P2\u2032\u200b=1.5kg\u00d71.0m\/s=1.5kg.m\/s So the <strong>Net Momentum<\/strong> after the collision is: Net\u00a0Momentum=0.75\u2009kg.m\/s+1.5\u2009kg.m\/s=2.25\u2009kg.m\/s\\text{Net Momentum} = 0.75 \\, \\text{kg.m\/s} + 1.5 \\, \\text{kg.m\/s} = 2.25 \\, \\text{kg.m\/s}Net\u00a0Momentum=0.75kg.m\/s+1.5kg.m\/s=2.25kg.m\/s This is the same as the net momentum before the collision.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Conclusion<\/strong>:<br>In an elastic collision, momentum is conserved, which means that the total net momentum before and after the collision remains the same. In this case, the total net momentum is 2.25 kg.m\/s both before and after the collision.<\/li>\n<\/ol>\n\n\n\n<p>This experiment demonstrates the principle of conservation of momentum in elastic collisions, where there is no loss of total momentum even though individual momenta of the objects may change.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-450.jpeg\" alt=\"\" class=\"wp-image-43246\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-450.jpeg 1024w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-450-300x300.jpeg 300w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-450-150x150.jpeg 150w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-450-768x768.jpeg 768w\" sizes=\"auto, (max-width: 1024px) 100vw, 1024px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>PhET Collision Lab Directions: Go to the website http:\/\/phet.colorado.edu\/en\/simulation\/collision-lab Make sure you will check \\&#8221;Advanced\\&#8221; and from there the 1-dimension box is checked. For the first simulation two masses must be equal. Right after the two ball collide stop the play. Momenta Scenario #1: Elastic collision between balls of equal mass Make a hypothesis about [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-43244","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/43244","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=43244"}],"version-history":[{"count":2,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/43244\/revisions"}],"predecessor-version":[{"id":43248,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/43244\/revisions\/43248"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=43244"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=43244"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=43244"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}