{"id":43207,"date":"2025-06-29T15:08:10","date_gmt":"2025-06-29T15:08:10","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=43207"},"modified":"2025-06-29T15:08:11","modified_gmt":"2025-06-29T15:08:11","slug":"write-a-molecular-ionic-and-net-ionic-equation-for-the-reaction-between-acetic-acid-ch3cooh-and-sodium-hydroxide","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/write-a-molecular-ionic-and-net-ionic-equation-for-the-reaction-between-acetic-acid-ch3cooh-and-sodium-hydroxide\/","title":{"rendered":"Write a molecular, ionic and net ionic equation for the reaction between acetic acid (CH3COOH) and sodium hydroxide."},"content":{"rendered":"\n<pre id=\"preorder-ask-header-text\" class=\"wp-block-preformatted\">Write a molecular, ionic and net ionic equation for the reaction between acetic acid (CH3COOH) and sodium hydroxide.<\/pre>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"875\" height=\"346\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/image-521.png\" alt=\"\" class=\"wp-image-43208\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/image-521.png 875w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/image-521-300x119.png 300w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/image-521-768x304.png 768w\" sizes=\"auto, (max-width: 875px) 100vw, 875px\" \/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To answer this question, let&#8217;s first break down the reaction between acetic acid (CH\u2083COOH) and sodium hydroxide (NaOH).<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Molecular Equation:<\/h3>\n\n\n\n<p>A molecular equation shows the complete compounds involved in a reaction without breaking them down into ions. When acetic acid reacts with sodium hydroxide, it forms sodium acetate and water. The molecular equation is:<\/p>\n\n\n\n<p><strong>CH\u2083COOH(aq) + NaOH(aq) \u2192 CH\u2083COONa(aq) + H\u2082O(l)<\/strong><\/p>\n\n\n\n<p>In this equation, acetic acid (CH\u2083COOH) reacts with sodium hydroxide (NaOH) to form sodium acetate (CH\u2083COONa) and water (H\u2082O).<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Ionic Equation:<\/h3>\n\n\n\n<p>An ionic equation separates all the strong electrolytes (soluble compounds) into their respective ions. Since sodium hydroxide (NaOH) and sodium acetate (CH\u2083COONa) are both strong electrolytes, they dissociate completely in water. The ionic equation is:<\/p>\n\n\n\n<p><strong>CH\u2083COOH(aq) + Na\u207a(aq) + OH\u207b(aq) \u2192 Na\u207a(aq) + CH\u2083COO\u207b(aq) + H\u2082O(l)<\/strong><\/p>\n\n\n\n<p>In this equation, we show sodium ions (Na\u207a) and hydroxide ions (OH\u207b) dissociating in solution.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Net Ionic Equation:<\/h3>\n\n\n\n<p>A net ionic equation removes the spectator ions (ions that appear on both sides of the equation). Spectator ions do not participate in the chemical change. In this case, Na\u207a is a spectator ion because it appears on both sides of the ionic equation. The net ionic equation is:<\/p>\n\n\n\n<p><strong>CH\u2083COOH(aq) + OH\u207b(aq) \u2192 CH\u2083COO\u207b(aq) + H\u2082O(l)<\/strong><\/p>\n\n\n\n<p>This is the simplified version of the ionic equation where only the species directly involved in the chemical reaction are shown.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Acetic acid (CH\u2083COOH) donates a hydrogen ion (H\u207a) to the hydroxide ion (OH\u207b) from sodium hydroxide (NaOH).<\/li>\n\n\n\n<li>This forms water (H\u2082O) and the acetate ion (CH\u2083COO\u207b).<\/li>\n\n\n\n<li>The sodium ion (Na\u207a) is a spectator ion and does not participate directly in the reaction, so it is omitted in the net ionic equation.<\/li>\n<\/ul>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-440.jpeg\" alt=\"\" class=\"wp-image-43209\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-440.jpeg 1024w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-440-300x300.jpeg 300w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-440-150x150.jpeg 150w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-440-768x768.jpeg 768w\" sizes=\"auto, (max-width: 1024px) 100vw, 1024px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Write a molecular, ionic and net ionic equation for the reaction between acetic acid (CH3COOH) and sodium hydroxide. The Correct Answer and Explanation is: To answer this question, let&#8217;s first break down the reaction between acetic acid (CH\u2083COOH) and sodium hydroxide (NaOH). Molecular Equation: A molecular equation shows the complete compounds involved in a reaction [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-43207","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/43207","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=43207"}],"version-history":[{"count":2,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/43207\/revisions"}],"predecessor-version":[{"id":43211,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/43207\/revisions\/43211"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=43207"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=43207"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=43207"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}