To calculate the mass in grams of a sample containing 7.35\u00d710237.35 \\times 10^{23}7.35\u00d71023 atoms of bismuth (Bi), we need to use the concept of moles and the molar mass.<\/p>\n\n\n\n
Step 1: Use Avogadro’s number<\/h3>\n\n\n\n
Avogadro’s number tells us that one mole of any substance contains 6.022\u00d710236.022 \\times 10^{23}6.022\u00d71023 particles (atoms, molecules, etc.). Therefore, we can calculate the number of moles of bismuth atoms in the given sample.<\/p>\n\n\n\n
The number of moles (nnn) is given by the formula: n=Number of atomsAvogadro\u2019s number=7.35\u00d710236.022\u00d71023n = \\frac{\\text{Number of atoms}}{\\text{Avogadro’s number}} = \\frac{7.35 \\times 10^{23}}{6.022 \\times 10^{23}}n=Avogadro\u2019s numberNumber of atoms\u200b=6.022\u00d710237.35\u00d71023\u200b<\/p>\n\n\n\n
This simplifies to: n=1.22 molesn = 1.22 \\text{ moles}n=1.22 moles<\/p>\n\n\n\n
Step 2: Calculate the mass using the molar mass<\/h3>\n\n\n\n
Now, we use the molar mass of bismuth to find the mass of the sample. The molar mass of bismuth (Bi) is 208.98\u2009g\/mol208.98 \\, \\text{g\/mol}208.98g\/mol. The formula to calculate the mass (mmm) is: m=n\u00d7Molar massm = n \\times \\text{Molar mass}m=n\u00d7Molar mass<\/p>\n\n\n\n
Substituting the values we have: m=1.22\u2009mol\u00d7208.98\u2009g\/molm = 1.22 \\, \\text{mol} \\times 208.98 \\, \\text{g\/mol}m=1.22mol\u00d7208.98g\/mol m=254.97\u2009gm = 254.97 \\, \\text{g}m=254.97g<\/p>\n\n\n\n
Step 3: Round to three significant figures<\/h3>\n\n\n\n
Since the problem asks for the answer in three significant figures, we round the result: m=255\u2009gm = 255 \\, \\text{g}m=255g<\/p>\n\n\n\n
Final Answer:<\/h3>\n\n\n\n
The mass of the bismuth sample is 255 grams<\/strong>.<\/p>\n\n\n\n The molar mass of bismuth (Bi) is 208.98 g\/mol. Calculate the mass in grams of a sample of Bi containing 7.35 \u00d7 10^23 atoms. Write your answer using three significant figures. (for this problem, do not use scientific notation) The Correct Answer and Explanation is: To calculate the mass in grams of a sample containing […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-42998","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/42998","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=42998"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/42998\/revisions"}],"predecessor-version":[{"id":43000,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/42998\/revisions\/43000"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=42998"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=42998"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=42998"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}![\"\"](\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-408.jpeg\")
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