{"id":42982,"date":"2025-06-29T12:37:01","date_gmt":"2025-06-29T12:37:01","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=42982"},"modified":"2025-06-29T12:37:03","modified_gmt":"2025-06-29T12:37:03","slug":"what-is-the-molar-mass-of-calcium-nitrate","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/what-is-the-molar-mass-of-calcium-nitrate\/","title":{"rendered":"What is the molar mass of calcium nitrate"},"content":{"rendered":"\n<p>What is the molar mass of calcium nitrate? (a) 150.08 g\/mol (b) 102.08 g\/mol (c) 164.09 g\/mol (d) 68.09 g\/mol<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The molar mass of calcium nitrate (Ca(NO\u2083)\u2082) can be calculated by adding up the atomic masses of all the elements in the formula. To break it down:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Calcium (Ca)<\/strong>: The atomic mass of calcium is approximately 40.08 g\/mol. Since there is 1 calcium atom in the formula, it contributes 40.08 g\/mol.<\/li>\n\n\n\n<li><strong>Nitrogen (N)<\/strong>: The atomic mass of nitrogen is approximately 14.01 g\/mol. There are 2 nitrogen atoms in the formula (from the two NO\u2083 groups), so the contribution from nitrogen is 2 \u00d7 14.01 g\/mol = 28.02 g\/mol.<\/li>\n\n\n\n<li><strong>Oxygen (O)<\/strong>: The atomic mass of oxygen is approximately 16.00 g\/mol. There are 6 oxygen atoms in the formula (since each nitrate group, NO\u2083, contains 3 oxygen atoms, and there are two NO\u2083 groups). The contribution from oxygen is 6 \u00d7 16.00 g\/mol = 96.00 g\/mol.<\/li>\n<\/ol>\n\n\n\n<p>Now, we can add these values together to find the molar mass:40.08\u2009g\/mol&nbsp;(Ca)+28.02\u2009g\/mol&nbsp;(N)+96.00\u2009g\/mol&nbsp;(O)=164.10\u2009g\/mol40.08 \\, \\text{g\/mol (Ca)} + 28.02 \\, \\text{g\/mol (N)} + 96.00 \\, \\text{g\/mol (O)} = 164.10 \\, \\text{g\/mol}40.08g\/mol&nbsp;(Ca)+28.02g\/mol&nbsp;(N)+96.00g\/mol&nbsp;(O)=164.10g\/mol<\/p>\n\n\n\n<p>Therefore, the correct answer is <strong>(c) 164.09 g\/mol<\/strong>, which is the molar mass of calcium nitrate.<\/p>\n\n\n\n<p>This mass represents the amount of calcium nitrate in one mole of the compound. The molar mass is essential for converting between grams and moles in chemical reactions.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-406.jpeg\" alt=\"\" class=\"wp-image-42987\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-406.jpeg 1024w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-406-300x300.jpeg 300w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-406-150x150.jpeg 150w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-406-768x768.jpeg 768w\" sizes=\"auto, (max-width: 1024px) 100vw, 1024px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>What is the molar mass of calcium nitrate? (a) 150.08 g\/mol (b) 102.08 g\/mol (c) 164.09 g\/mol (d) 68.09 g\/mol The Correct Answer and Explanation is: The molar mass of calcium nitrate (Ca(NO\u2083)\u2082) can be calculated by adding up the atomic masses of all the elements in the formula. To break it down: Now, we [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-42982","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/42982","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=42982"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/42982\/revisions"}],"predecessor-version":[{"id":42992,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/42982\/revisions\/42992"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=42982"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=42982"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=42982"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}