{"id":42656,"date":"2025-06-29T07:57:53","date_gmt":"2025-06-29T07:57:53","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=42656"},"modified":"2025-06-29T07:57:54","modified_gmt":"2025-06-29T07:57:54","slug":"calculate-the-percent-composition-by-mass-of-magnesium-in-mgno32","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/calculate-the-percent-composition-by-mass-of-magnesium-in-mgno32\/","title":{"rendered":"Calculate the percent composition by mass of magnesium in Mg(NO3)2."},"content":{"rendered":"\n<p>Calculate the percent composition by mass of magnesium in Mg(NO3)2.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To calculate the percent composition by mass of magnesium in magnesium nitrate, Mg(NO3)2\\text{Mg(NO}_3)_2Mg(NO3\u200b)2\u200b, follow these steps:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Find the molar mass of Mg(NO3)2\\text{Mg(NO}_3)_2Mg(NO3\u200b)2\u200b<\/h3>\n\n\n\n<p>Start by calculating the molar mass of magnesium nitrate. This involves adding the molar masses of each element in the compound. The atomic masses are approximately:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Magnesium (Mg) = 24.31 g\/mol<\/li>\n\n\n\n<li>Nitrogen (N) = 14.01 g\/mol<\/li>\n\n\n\n<li>Oxygen (O) = 16.00 g\/mol<\/li>\n<\/ul>\n\n\n\n<p>Now, break down the compound Mg(NO3)2\\text{Mg(NO}_3)_2Mg(NO3\u200b)2\u200b:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>One magnesium atom: 1\u00d724.31=24.31\u2009g\/mol1 \\times 24.31 = 24.31 \\, \\text{g\/mol}1\u00d724.31=24.31g\/mol<\/li>\n\n\n\n<li>Two nitrate ions, NO3\\text{NO}_3NO3\u200b: Each nitrate consists of one nitrogen atom and three oxygen atoms. Therefore:\n<ul class=\"wp-block-list\">\n<li>Nitrogen: 2\u00d714.01=28.02\u2009g\/mol2 \\times 14.01 = 28.02 \\, \\text{g\/mol}2\u00d714.01=28.02g\/mol<\/li>\n\n\n\n<li>Oxygen: 6\u00d716.00=96.00\u2009g\/mol6 \\times 16.00 = 96.00 \\, \\text{g\/mol}6\u00d716.00=96.00g\/mol<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<p>Now add all these together:Molar&nbsp;mass&nbsp;of&nbsp;Mg(NO3)2=24.31+28.02+96.00=148.33\u2009g\/mol\\text{Molar mass of Mg(NO}_3)_2 = 24.31 + 28.02 + 96.00 = 148.33 \\, \\text{g\/mol}Molar&nbsp;mass&nbsp;of&nbsp;Mg(NO3\u200b)2\u200b=24.31+28.02+96.00=148.33g\/mol<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Calculate the mass percent of magnesium<\/h3>\n\n\n\n<p>Next, calculate the mass percent of magnesium in magnesium nitrate by dividing the mass of magnesium by the total molar mass of the compound and then multiplying by 100:Percent&nbsp;of&nbsp;Mg=(24.31148.33)\u00d7100=16.4%\\text{Percent of Mg} = \\left( \\frac{24.31}{148.33} \\right) \\times 100 = 16.4\\%Percent&nbsp;of&nbsp;Mg=(148.3324.31\u200b)\u00d7100=16.4%<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion:<\/h3>\n\n\n\n<p>The percent composition by mass of magnesium in Mg(NO3)2\\text{Mg(NO}_3)_2Mg(NO3\u200b)2\u200b is approximately <strong>16.4%<\/strong>. This means that 16.4% of the mass of magnesium nitrate is contributed by magnesium.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-349.jpeg\" alt=\"\" class=\"wp-image-42657\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-349.jpeg 1024w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-349-300x300.jpeg 300w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-349-150x150.jpeg 150w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-349-768x768.jpeg 768w\" sizes=\"auto, (max-width: 1024px) 100vw, 1024px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Calculate the percent composition by mass of magnesium in Mg(NO3)2. The Correct Answer and Explanation is: To calculate the percent composition by mass of magnesium in magnesium nitrate, Mg(NO3)2\\text{Mg(NO}_3)_2Mg(NO3\u200b)2\u200b, follow these steps: Step 1: Find the molar mass of Mg(NO3)2\\text{Mg(NO}_3)_2Mg(NO3\u200b)2\u200b Start by calculating the molar mass of magnesium nitrate. This involves adding the molar masses [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-42656","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/42656","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=42656"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/42656\/revisions"}],"predecessor-version":[{"id":42658,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/42656\/revisions\/42658"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=42656"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=42656"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=42656"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}