{"id":42554,"date":"2025-06-29T06:11:58","date_gmt":"2025-06-29T06:11:58","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=42554"},"modified":"2025-06-29T06:12:00","modified_gmt":"2025-06-29T06:12:00","slug":"convert-3-01-x-10-exponent-23-molecules-of-c2h6-to-moles","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/convert-3-01-x-10-exponent-23-molecules-of-c2h6-to-moles\/","title":{"rendered":"Convert 3.01 x 10 exponent 23 molecules of C2H6 to moles."},"content":{"rendered":"\n

Convert 3.01 x 10 exponent 23 molecules of C2H6 to moles. can someone teach me too- this was my hardest TvT<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

To convert 3.01\u00d710233.01 \\times 10^{23}3.01\u00d71023 molecules of C2H6C_2H_6C2\u200bH6\u200b (ethane) to moles, you need to understand the relationship between molecules and moles.<\/p>\n\n\n\n

    \n
  1. Avogadro\u2019s Number<\/strong>: This is the key constant you’ll use. It tells you how many molecules are in one mole of any substance. Avogadro’s number is: 6.022\u00d71023\u2009molecules\/mole6.022 \\times 10^{23} \\, \\text{molecules\/mole}6.022\u00d71023molecules\/mole<\/li>\n\n\n\n
  2. Convert molecules to moles<\/strong>: To convert molecules into moles, you divide the number of molecules by Avogadro\u2019s number. The formula looks like this: Moles\u00a0of\u00a0C2H6=Number\u00a0of\u00a0molecules\u00a0of\u00a0C2H6Avogadro\u2019s\u00a0number\\text{Moles of } C_2H_6 = \\frac{\\text{Number of molecules of } C_2H_6}{\\text{Avogadro’s number}}Moles\u00a0of\u00a0C2\u200bH6\u200b=Avogadro\u2019s\u00a0numberNumber\u00a0of\u00a0molecules\u00a0of\u00a0C2\u200bH6\u200b\u200b Plugging in the numbers: Moles\u00a0of\u00a0C2H6=3.01\u00d710236.022\u00d71023\u2009moles\\text{Moles of } C_2H_6 = \\frac{3.01 \\times 10^{23}}{6.022 \\times 10^{23}} \\, \\text{moles}Moles\u00a0of\u00a0C2\u200bH6\u200b=6.022\u00d710233.01\u00d71023\u200bmoles<\/li>\n\n\n\n
  3. Simplify<\/strong>: When you divide the exponents, you get: Moles\u00a0of\u00a0C2H6=0.5\u2009moles\\text{Moles of } C_2H_6 = 0.5 \\, \\text{moles}Moles\u00a0of\u00a0C2\u200bH6\u200b=0.5moles<\/li>\n<\/ol>\n\n\n\n

    So, 3.01\u00d710233.01 \\times 10^{23}3.01\u00d71023 molecules of C2H6C_2H_6C2\u200bH6\u200b is equal to 0.5 moles of ethane.<\/p>\n\n\n\n

    Explanation:<\/h3>\n\n\n\n
      \n
    • Avogadro’s number<\/strong> represents the number of molecules or atoms in one mole of any substance.<\/li>\n\n\n\n
    • When you have a number of molecules (in this case, 3.01\u00d710233.01 \\times 10^{23}3.01\u00d71023), you can divide by Avogadro\u2019s number to find how many moles it represents.<\/li>\n\n\n\n
    • The result shows that you have half a mole (0.5 moles) of C2H6C_2H_6C2\u200bH6\u200b, since 3.01\u00d710233.01 \\times 10^{23}3.01\u00d71023 is about half of 6.022\u00d710236.022 \\times 10^{23}6.022\u00d71023.<\/li>\n<\/ul>\n\n\n\n

      It’s all about using Avogadro’s number to convert between molecules and moles! It might be tricky at first, but once you understand the concept, it gets easier.<\/p>\n\n\n\n

      \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

      Convert 3.01 x 10 exponent 23 molecules of C2H6 to moles. can someone teach me too- this was my hardest TvT The Correct Answer and Explanation is: To convert 3.01\u00d710233.01 \\times 10^{23}3.01\u00d71023 molecules of C2H6C_2H_6C2\u200bH6\u200b (ethane) to moles, you need to understand the relationship between molecules and moles. So, 3.01\u00d710233.01 \\times 10^{23}3.01\u00d71023 molecules of C2H6C_2H_6C2\u200bH6\u200b […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-42554","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/42554","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=42554"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/42554\/revisions"}],"predecessor-version":[{"id":42556,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/42554\/revisions\/42556"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=42554"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=42554"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=42554"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}