What is the molar mass of AlCl3?<\/p>\n\n\n\n
The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n Correct Answer:<\/strong><\/p>\n\n\n\n The molar mass of AlCl\u2083 (Aluminum chloride)<\/strong> is 133.33 g\/mol<\/strong>.<\/p>\n\n\n\n Explanation:<\/strong><\/p>\n\n\n\n To calculate the molar mass of a compound, sum the atomic masses of all the atoms present in the formula. The atomic masses used are taken from the periodic table and expressed in grams per mole (g\/mol).<\/p>\n\n\n\n AlCl\u2083 contains:<\/p>\n\n\n\n From the periodic table:<\/p>\n\n\n\n Now calculate: Molar mass of AlCl3=(1\u00d726.98)+(3\u00d735.45)\\text{Molar mass of AlCl}_3 = (1 \\times 26.98) + (3 \\times 35.45) =26.98+106.35=133.33\u2009g\/mol= 26.98 + 106.35 = 133.33 \\, \\text{g\/mol}<\/p>\n\n\n\n This value represents the mass of one mole of aluminum chloride molecules. Molar mass is important in chemistry because it allows conversion between grams and moles of a substance, which is critical for quantitative chemical calculations.<\/p>\n\n\n\n For instance, if someone has 10 grams of AlCl\u2083 and wants to know how many moles that is, they would divide the mass by the molar mass: Moles of AlCl3=10\u2009g133.33\u2009g\/mol\u22480.075\u2009mol\\text{Moles of AlCl}_3 = \\frac{10 \\, \\text{g}}{133.33 \\, \\text{g\/mol}} \\approx 0.075 \\, \\text{mol}<\/p>\n\n\n\n This is useful in stoichiometry, where balanced chemical equations help determine the proportions of reactants and products. The molar mass of AlCl\u2083 also helps in preparing solutions of known concentration and in analyzing chemical reactions that involve aluminum chloride.<\/p>\n\n\n\n Understanding molar mass is a foundation in chemistry because it bridges the microscopic world of atoms and molecules with the measurable quantities used in laboratories.<\/p>\n","protected":false},"excerpt":{"rendered":" What is the molar mass of AlCl3? The correct answer and explanation is: Correct Answer: The molar mass of AlCl\u2083 (Aluminum chloride) is 133.33 g\/mol. Explanation: To calculate the molar mass of a compound, sum the atomic masses of all the atoms present in the formula. The atomic masses used are taken from the periodic […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-41584","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/41584","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=41584"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/41584\/revisions"}],"predecessor-version":[{"id":41585,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/41584\/revisions\/41585"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=41584"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=41584"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=41584"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
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