{"id":41468,"date":"2025-06-28T08:49:11","date_gmt":"2025-06-28T08:49:11","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=41468"},"modified":"2025-06-28T08:49:12","modified_gmt":"2025-06-28T08:49:12","slug":"which-of-the-following-has-eight-valence-electrons","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/which-of-the-following-has-eight-valence-electrons\/","title":{"rendered":"Which of the following has eight valence electrons"},"content":{"rendered":"\n<p>Which of the following has eight valence electrons? Ti4+ Kr Cl- Na+ all of the above<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Correct Answer: All of the above<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>To determine which of the listed species has <strong>eight valence electrons<\/strong>, we must consider the <strong>electron configuration<\/strong> of each atom or ion. An atom or ion with a <strong>full outer shell<\/strong> of <strong>eight electrons<\/strong> is said to have achieved a <strong>stable noble gas configuration<\/strong>, which is also known as the <strong>octet rule<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Ti\u2074\u207a (Titanium ion with a +4 charge):<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Titanium has an atomic number of 22.<\/li>\n\n\n\n<li>Neutral titanium has the electron configuration: 1s\u00b2 2s\u00b2 2p\u2076 3s\u00b2 3p\u2076 3d\u00b2 4s\u00b2.<\/li>\n\n\n\n<li>Losing four electrons (to become Ti\u2074\u207a) removes the 4s\u00b2 and 3d\u00b2 electrons.<\/li>\n\n\n\n<li>Ti\u2074\u207a becomes: 1s\u00b2 2s\u00b2 2p\u2076 3s\u00b2 3p\u2076 \u2192 this is the same configuration as <strong>argon (Ar)<\/strong>.<\/li>\n\n\n\n<li>Argon has eight electrons in its outermost shell.<\/li>\n\n\n\n<li>So <strong>Ti\u2074\u207a has eight valence electrons<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<ol start=\"2\" class=\"wp-block-list\">\n<li><strong>Kr (Krypton):<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Krypton is a noble gas with atomic number 36.<\/li>\n\n\n\n<li>Its full configuration ends in: 4s\u00b2 3d\u00b9\u2070 4p\u2076.<\/li>\n\n\n\n<li>The outermost shell (n = 4) has 2 (from 4s) + 6 (from 4p) = <strong>8 valence electrons<\/strong>.<\/li>\n\n\n\n<li>So <strong>Kr has eight valence electrons<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<ol start=\"3\" class=\"wp-block-list\">\n<li><strong>Cl\u207b (Chloride ion):<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Chlorine has an atomic number of 17: 1s\u00b2 2s\u00b2 2p\u2076 3s\u00b2 3p\u2075.<\/li>\n\n\n\n<li>When it gains one electron to become Cl\u207b, the configuration becomes: 3s\u00b2 3p\u2076.<\/li>\n\n\n\n<li>The outer shell now has 2 + 6 = <strong>8 valence electrons<\/strong>.<\/li>\n\n\n\n<li>So <strong>Cl\u207b has eight valence electrons<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<ol start=\"4\" class=\"wp-block-list\">\n<li><strong>Na\u207a (Sodium ion):<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Sodium has an atomic number of 11.<\/li>\n\n\n\n<li>Neutral sodium: 1s\u00b2 2s\u00b2 2p\u2076 3s\u00b9.<\/li>\n\n\n\n<li>Na\u207a loses the one 3s electron, leaving: 1s\u00b2 2s\u00b2 2p\u2076 \u2192 same as <strong>neon (Ne)<\/strong>.<\/li>\n\n\n\n<li>That is <strong>8 valence electrons<\/strong> in the second shell.<\/li>\n\n\n\n<li>So <strong>Na\u207a has eight valence electrons<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Conclusion:<\/strong> All of the listed atoms or ions have <strong>eight valence electrons<\/strong>, which makes <strong>\u201cAll of the above\u201d<\/strong> the correct choice.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1339.jpeg\" alt=\"\" class=\"wp-image-41472\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1339.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1339-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1339-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Which of the following has eight valence electrons? Ti4+ Kr Cl- Na+ all of the above The Correct Answer and Explanation is: Correct Answer: All of the above Explanation: To determine which of the listed species has eight valence electrons, we must consider the electron configuration of each atom or ion. An atom or ion [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-41468","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/41468","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=41468"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/41468\/revisions"}],"predecessor-version":[{"id":41477,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/41468\/revisions\/41477"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=41468"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=41468"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=41468"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}