{"id":40929,"date":"2025-06-27T21:28:33","date_gmt":"2025-06-27T21:28:33","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=40929"},"modified":"2025-06-27T21:28:34","modified_gmt":"2025-06-27T21:28:34","slug":"what-is-the-formula-of-the-precipitate-that-forms-when-aqueous-ammonium-phosphate-nh43po4-and-aqueous-copperii-chloride-are-mixed","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/what-is-the-formula-of-the-precipitate-that-forms-when-aqueous-ammonium-phosphate-nh43po4-and-aqueous-copperii-chloride-are-mixed\/","title":{"rendered":"What is the formula of the precipitate that forms when aqueous ammonium phosphate (NH4)3PO4 and aqueous copper(II) chloride are mixed"},"content":{"rendered":"\n<p>What is the formula of the precipitate that forms when aqueous ammonium phosphate (NH4)3PO4 and aqueous copper(II) chloride are mixed? Group of answer choices Cu3(PO4)2 Cu(NH4)2 Cu3P2 Cu2Cl3<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Correct Answer:<\/strong> <strong>Cu\u2083(PO\u2084)\u2082<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>When aqueous <strong>ammonium phosphate<\/strong> (NH4)3PO4(NH_4)_3PO_4(NH4\u200b)3\u200bPO4\u200b and <strong>copper(II) chloride<\/strong> CuCl2\\mathrm{CuCl_2}CuCl2\u200b are mixed, a <strong>double displacement reaction<\/strong> occurs. In this reaction, the positive ions (cations) and negative ions (anions) from both compounds switch partners, potentially forming a precipitate if an insoluble product results.<\/p>\n\n\n\n<p><strong>Step 1: Identify the ions present<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Ammonium phosphate (NH4)3PO4(NH_4)_3PO_4(NH4\u200b)3\u200bPO4\u200b dissociates into:\n<ul class=\"wp-block-list\">\n<li>3 Ammonium ions (NH4+)(NH_4^+)(NH4+\u200b)<\/li>\n\n\n\n<li>1 Phosphate ion (PO43\u2212)(PO_4^{3-})(PO43\u2212\u200b)<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Copper(II) chloride CuCl2\\mathrm{CuCl_2}CuCl2\u200b dissociates into:\n<ul class=\"wp-block-list\">\n<li>1 Copper(II) ion (Cu2+)(Cu^{2+})(Cu2+)<\/li>\n\n\n\n<li>2 Chloride ions (Cl\u2212)(Cl^-)(Cl\u2212)<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<p><strong>Step 2: Predict the products<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The copper(II) ions (Cu2+)(Cu^{2+})(Cu2+) will combine with phosphate ions (PO43\u2212)(PO_4^{3-})(PO43\u2212\u200b)<\/li>\n\n\n\n<li>The ammonium ions (NH4+)(NH_4^+)(NH4+\u200b) will combine with chloride ions (Cl\u2212)(Cl^-)(Cl\u2212)<\/li>\n<\/ul>\n\n\n\n<p>The precipitate forms if one of the products is insoluble in water. According to solubility rules:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Most phosphates (PO43\u2212)(PO_4^{3-})(PO43\u2212\u200b) are <strong>insoluble<\/strong>, except those with ammonium or alkali metals<\/li>\n\n\n\n<li>Copper(II) phosphate (Cu3(PO4)2)(Cu_3(PO_4)_2)(Cu3\u200b(PO4\u200b)2\u200b) is <strong>insoluble<\/strong>, forming a solid precipitate<\/li>\n\n\n\n<li>Ammonium chloride (NH4Cl)(NH_4Cl)(NH4\u200bCl) is soluble and remains in solution<\/li>\n<\/ul>\n\n\n\n<p><strong>Step 3: Write the balanced molecular equation<\/strong>2(NH4)3PO4(aq)+3CuCl2(aq)\u2192Cu3(PO4)2(s)+6NH4Cl(aq)2(NH_4)_3PO_4(aq) + 3CuCl_2(aq) \\rightarrow Cu_3(PO_4)_2(s) + 6NH_4Cl(aq)2(NH4\u200b)3\u200bPO4\u200b(aq)+3CuCl2\u200b(aq)\u2192Cu3\u200b(PO4\u200b)2\u200b(s)+6NH4\u200bCl(aq)<\/p>\n\n\n\n<p><strong>Step 4: Determine the precipitate formula<\/strong><\/p>\n\n\n\n<p>The formula of the precipitate is <strong>copper(II) phosphate<\/strong>, written as:Cu3(PO4)2Cu_3(PO_4)_2Cu3\u200b(PO4\u200b)2\u200b<\/p>\n\n\n\n<p>Thus, the correct answer is <strong>Cu\u2083(PO\u2084)\u2082<\/strong>. The other options:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Cu(NH\u2084)\u2082<\/strong> is incorrect because copper does not form this compound in the given reaction<\/li>\n\n\n\n<li><strong>Cu\u2083P\u2082<\/strong> is incorrect, it represents copper phosphide, not relevant here<\/li>\n\n\n\n<li><strong>Cu\u2082Cl\u2083<\/strong> is incorrect as copper chloride typically forms as CuCl or CuCl\u2082<\/li>\n<\/ul>\n\n\n\n<p>Therefore, <strong>Cu\u2083(PO\u2084)\u2082<\/strong> is the correct precipitate formed.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1290.jpeg\" alt=\"\" class=\"wp-image-40949\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1290.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1290-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1290-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>What is the formula of the precipitate that forms when aqueous ammonium phosphate (NH4)3PO4 and aqueous copper(II) chloride are mixed? Group of answer choices Cu3(PO4)2 Cu(NH4)2 Cu3P2 Cu2Cl3 The Correct Answer and Explanation is: Correct Answer: Cu\u2083(PO\u2084)\u2082 Explanation: When aqueous ammonium phosphate (NH4)3PO4(NH_4)_3PO_4(NH4\u200b)3\u200bPO4\u200b and copper(II) chloride CuCl2\\mathrm{CuCl_2}CuCl2\u200b are mixed, a double displacement reaction occurs. In [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-40929","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/40929","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=40929"}],"version-history":[{"count":2,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/40929\/revisions"}],"predecessor-version":[{"id":40951,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/40929\/revisions\/40951"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=40929"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=40929"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=40929"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}