{"id":40645,"date":"2025-06-27T18:59:20","date_gmt":"2025-06-27T18:59:20","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=40645"},"modified":"2025-06-27T18:59:21","modified_gmt":"2025-06-27T18:59:21","slug":"fogohx-fghx","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/fogohx-fghx\/","title":{"rendered":"fogoh(x) = f(g(h(x)))"},"content":{"rendered":"\n<p>fogoh(x) = f(g(h(x)))<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To find <strong>fogoh(x) = f(g(h(x)))<\/strong>, you need to understand function composition step by step.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Understand Function Composition<\/h3>\n\n\n\n<p>Function composition means applying one function to the results of another function. The notation <strong>fogoh(x)<\/strong> represents applying <strong>h(x)<\/strong> first, then plugging that result into <strong>g(x)<\/strong>, and finally plugging that into <strong>f(x)<\/strong>.<\/p>\n\n\n\n<p>The expression breaks down like this:<br><strong>fogoh(x) = f(g(h(x)))<\/strong><\/p>\n\n\n\n<p>This means:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>Start with <strong>x<\/strong> and apply the function <strong>h<\/strong>, so you get <strong>h(x)<\/strong><\/li>\n\n\n\n<li>Take that result and apply the function <strong>g<\/strong>, giving <strong>g(h(x))<\/strong><\/li>\n\n\n\n<li>Finally, apply the function <strong>f<\/strong> to the result, which gives <strong>f(g(h(x)))<\/strong><\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Example with Defined Functions<\/h3>\n\n\n\n<p>Suppose:<br><strong>h(x) = x + 1<\/strong><br><strong>g(x) = 2x<\/strong><br><strong>f(x) = x\u00b2<\/strong><\/p>\n\n\n\n<p>We are asked to find <strong>fogoh(x)<\/strong>, which means <strong>f(g(h(x)))<\/strong>.<\/p>\n\n\n\n<p><strong>First<\/strong>, compute <strong>h(x)<\/strong>:<br><strong>h(x) = x + 1<\/strong><\/p>\n\n\n\n<p><strong>Second<\/strong>, compute <strong>g(h(x))<\/strong>:<br><strong>g(h(x)) = g(x + 1) = 2(x + 1) = 2x + 2<\/strong><\/p>\n\n\n\n<p><strong>Third<\/strong>, compute <strong>f(g(h(x)))<\/strong>:<br><strong>f(g(h(x))) = f(2x + 2) = (2x + 2)\u00b2 = 4x\u00b2 + 8x + 4<\/strong><\/p>\n\n\n\n<p>Thus, the final answer is:<br><strong>fogoh(x) = 4x\u00b2 + 8x + 4<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Importance of Function Composition<\/h3>\n\n\n\n<p>Function composition allows complex operations by combining simpler functions. In mathematics, this is used in algebra, calculus, and real-world modeling. Each function represents a transformation or a process, and composing them shows how several processes affect a quantity step by step.<\/p>\n\n\n\n<p>The order matters greatly in composition. Applying <strong>h<\/strong>, then <strong>g<\/strong>, then <strong>f<\/strong> is different from changing the order. You must carefully follow the sequence to avoid mistakes.<\/p>\n\n\n\n<p>In conclusion, <strong>fogoh(x) = f(g(h(x)))<\/strong> means applying functions stepwise in the given order to compute the final output accurately.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1279.jpeg\" alt=\"\" class=\"wp-image-40657\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1279.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1279-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1279-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>fogoh(x) = f(g(h(x))) The Correct Answer and Explanation is: To find fogoh(x) = f(g(h(x))), you need to understand function composition step by step. Step 1: Understand Function Composition Function composition means applying one function to the results of another function. The notation fogoh(x) represents applying h(x) first, then plugging that result into g(x), and finally [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-40645","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/40645","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=40645"}],"version-history":[{"count":2,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/40645\/revisions"}],"predecessor-version":[{"id":40660,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/40645\/revisions\/40660"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=40645"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=40645"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=40645"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}