{"id":39982,"date":"2025-06-27T11:57:07","date_gmt":"2025-06-27T11:57:07","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=39982"},"modified":"2025-06-27T11:57:08","modified_gmt":"2025-06-27T11:57:08","slug":"balance-the-following-equation-nh3-o2%e2%86%92-no-h2o","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/balance-the-following-equation-nh3-o2%e2%86%92-no-h2o\/","title":{"rendered":"Balance the following equation: NH3 + O2\u2192 NO + H2O"},"content":{"rendered":"\n<p>Balance the following equation: NH3 + O2\u2192 NO + H2O<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Balanced Chemical Equation:<\/strong><\/p>\n\n\n\n<p>4 NH\u2083 + 3 O\u2082 \u2192 4 NO + 6 H\u2082O<\/p>\n\n\n\n<p><strong>Explanation:<\/strong><\/p>\n\n\n\n<p>To balance a chemical equation, the number of atoms of each element on the reactant side must equal the number on the product side. This follows the Law of Conservation of Mass, which states that matter is neither created nor destroyed in a chemical reaction.<\/p>\n\n\n\n<p>The unbalanced equation is:<br>NH\u2083 + O\u2082 \u2192 NO + H\u2082O<\/p>\n\n\n\n<p>Start with nitrogen (N). Each molecule of NH\u2083 has 1 nitrogen atom, and each NO molecule on the product side also contains 1 nitrogen atom. Begin by placing a 4 in front of NH\u2083 and NO:<br>4 NH\u2083 + O\u2082 \u2192 4 NO + H\u2082O<\/p>\n\n\n\n<p>Now, balance hydrogen (H). Each NH\u2083 molecule has 3 hydrogen atoms, so 4 NH\u2083 molecules provide 12 hydrogen atoms. These hydrogen atoms appear in H\u2082O on the product side. Each H\u2082O has 2 hydrogen atoms, so 6 H\u2082O molecules are needed to give 12 hydrogen atoms:<br>4 NH\u2083 + O\u2082 \u2192 4 NO + 6 H\u2082O<\/p>\n\n\n\n<p>Next, balance oxygen (O). On the product side, there are 4 oxygen atoms from 4 NO and 6 oxygen atoms from 6 H\u2082O, giving a total of 10 oxygen atoms. O\u2082 is the oxygen source on the reactant side, and each O\u2082 molecule has 2 oxygen atoms. To get 10 oxygen atoms, 5 O\u2082 molecules are needed:<br>4 NH\u2083 + <strong>5<\/strong> O\u2082 \u2192 4 NO + 6 H\u2082O<\/p>\n\n\n\n<p>However, this leads to an imbalance. There must have been a mistake in the oxygen count. Re-examine it.<\/p>\n\n\n\n<p>From 4 NO: 4 O atoms<br>From 6 H\u2082O: 6 O atoms<br>Total: 4 + 6 = 10 O atoms<br>So, use 5 O\u2082 molecules to get 10 O atoms:<br>4 NH\u2083 + 5 O\u2082 \u2192 4 NO + 6 H\u2082O<\/p>\n\n\n\n<p>Now all elements are balanced:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>N: 4 on each side<\/li>\n\n\n\n<li>H: 12 on each side<\/li>\n\n\n\n<li>O: 10 on each side<\/li>\n<\/ul>\n\n\n\n<p>The balanced equation is:<br><strong>4 NH\u2083 + 5 O\u2082 \u2192 4 NO + 6 H\u2082O<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Balance the following equation: NH3 + O2\u2192 NO + H2O The correct answer and explanation is: Balanced Chemical Equation: 4 NH\u2083 + 3 O\u2082 \u2192 4 NO + 6 H\u2082O Explanation: To balance a chemical equation, the number of atoms of each element on the reactant side must equal the number on the product side. [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-39982","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/39982","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=39982"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/39982\/revisions"}],"predecessor-version":[{"id":39983,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/39982\/revisions\/39983"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=39982"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=39982"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=39982"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}