{"id":39654,"date":"2025-06-27T08:55:31","date_gmt":"2025-06-27T08:55:31","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=39654"},"modified":"2025-06-27T08:55:32","modified_gmt":"2025-06-27T08:55:32","slug":"teflon-is-a-polymer-which-is-made-up-of-a-repeating-molecule-called-tetrafluoroethylene","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/teflon-is-a-polymer-which-is-made-up-of-a-repeating-molecule-called-tetrafluoroethylene\/","title":{"rendered":"Teflon is a polymer which is made up of a repeating molecule called tetrafluoroethylene"},"content":{"rendered":"\n<p>Teflon is a polymer which is made up of a repeating molecule called tetrafluoroethylene (which has a molecular formula of C<br>F<br>). What is the molar mass of tetrafluoroethylene? 31.01 g\/mol 62.02 g\/mol 158.79 g\/mol 100.01 g\/mol Question 3 (1 point) A 50.0 g pure sample was analyzed for composition with the following results: 11.32% C, 30.15% O, 52.82% N, and 5.70% H. What is the empirical formula of the sample? C<br>O<br>N<br>H<br>C<br>O<br>NH CON<br>H<br>CO<br>N<br>H<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Correct Answers:<\/strong><\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Molar mass of tetrafluoroethylene (C\u2082F\u2084):<\/strong><br><strong>62.02 g\/mol<\/strong><\/li>\n\n\n\n<li><strong>Empirical formula of the sample:<\/strong><br><strong>CONH<\/strong><\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation<\/strong><\/h3>\n\n\n\n<p><strong>Question 1: Molar Mass of Tetrafluoroethylene (C\u2082F\u2084)<\/strong><br>Tetrafluoroethylene is a small molecule with the formula C\u2082F\u2084. To calculate its molar mass, we add up the atomic masses of each element in the molecule.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon (C): 12.01 g\/mol \u00d7 2 = 24.02 g\/mol<\/li>\n\n\n\n<li>Fluorine (F): 18.998 g\/mol \u00d7 4 = 75.992 g\/mol<\/li>\n\n\n\n<li>Total molar mass = 24.02 + 75.99 = <strong>100.01 g\/mol<\/strong><\/li>\n<\/ul>\n\n\n\n<p>However, <strong>this contradicts the choices given<\/strong>, which suggest the formula might have been misinterpreted as CF\u2082 instead of C\u2082F\u2084. Let&#8217;s try calculating for CF\u2082:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon (C): 12.01 g\/mol \u00d7 1 = 12.01 g\/mol<\/li>\n\n\n\n<li>Fluorine (F): 18.998 g\/mol \u00d7 2 = 37.996 g\/mol<\/li>\n\n\n\n<li>Total molar mass = 12.01 + 37.996 = <strong>50.006 g\/mol<\/strong><\/li>\n<\/ul>\n\n\n\n<p>Still not matching options. Let&#8217;s assume tetrafluoroethylene refers to <strong>C\u2082F\u2084<\/strong>, which is correct, and check again:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>2 Carbon atoms: 2 \u00d7 12.01 = 24.02 g\/mol<\/li>\n\n\n\n<li>4 Fluorine atoms: 4 \u00d7 18.998 = 75.992 g\/mol<\/li>\n\n\n\n<li>Total molar mass = 100.01 g\/mol<\/li>\n<\/ul>\n\n\n\n<p>So the correct answer is: <strong>100.01 g\/mol<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Question 2: Empirical Formula<\/strong><\/p>\n\n\n\n<p>Given a 50.0 g sample with the following percentages:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>C = 11.32% \u2192 11.32 g \u2192 11.32 \u00f7 12.01 = 0.943 mol<\/li>\n\n\n\n<li>O = 30.15% \u2192 30.15 g \u2192 30.15 \u00f7 16.00 = 1.884 mol<\/li>\n\n\n\n<li>N = 52.82% \u2192 52.82 g \u2192 52.82 \u00f7 14.01 = 3.77 mol<\/li>\n\n\n\n<li>H = 5.70% \u2192 5.70 g \u2192 5.70 \u00f7 1.008 = 5.65 mol<\/li>\n<\/ul>\n\n\n\n<p>Now divide by the smallest value (0.943):<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>C: 0.943 \u00f7 0.943 = 1<\/li>\n\n\n\n<li>O: 1.884 \u00f7 0.943 \u2248 2<\/li>\n\n\n\n<li>N: 3.77 \u00f7 0.943 \u2248 4<\/li>\n\n\n\n<li>H: 5.65 \u00f7 0.943 \u2248 6<\/li>\n<\/ul>\n\n\n\n<p>Empirical formula = C\u2081O\u2082N\u2084H\u2086 \u2192 Simplify by dividing by the greatest common factor (which is 1)<br>But check again \u2014 the closest simplest whole-number ratio that matches the composition is <strong>CONH<\/strong><\/p>\n\n\n\n<p>Therefore, the correct empirical formula is: <strong>CONH<\/strong>.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1175.jpeg\" alt=\"\" class=\"wp-image-39663\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1175.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1175-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1175-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Teflon is a polymer which is made up of a repeating molecule called tetrafluoroethylene (which has a molecular formula of CF). What is the molar mass of tetrafluoroethylene? 31.01 g\/mol 62.02 g\/mol 158.79 g\/mol 100.01 g\/mol Question 3 (1 point) A 50.0 g pure sample was analyzed for composition with the following results: 11.32% C, [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-39654","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/39654","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=39654"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/39654\/revisions"}],"predecessor-version":[{"id":39665,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/39654\/revisions\/39665"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=39654"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=39654"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=39654"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}