{"id":39649,"date":"2025-06-27T08:52:16","date_gmt":"2025-06-27T08:52:16","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=39649"},"modified":"2025-06-27T08:52:17","modified_gmt":"2025-06-27T08:52:17","slug":"how-many-grams-of-fluorine-are-in-35-2-kg-of-c2f4","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/how-many-grams-of-fluorine-are-in-35-2-kg-of-c2f4\/","title":{"rendered":"How many grams of fluorine are in 35.2 kg of C2F4"},"content":{"rendered":"\n<p>How many grams of fluorine are in 35.2 kg of C2F4 (molar mass = 100.02 g\/mol)?<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To find how many grams of fluorine are in 35.2 kg of C\u2082F\u2084, follow these steps:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Step 1: Convert kilograms of C\u2082F\u2084 to grams<\/strong><\/p>\n\n\n\n<p>35.2 kg \u00d7 1,000 g\/kg = 35,200 g of C\u2082F\u2084<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Step 2: Calculate the number of moles of C\u2082F\u2084<\/strong><\/p>\n\n\n\n<p>Number of moles = mass \/ molar mass<br>= 35,200 g \/ 100.02 g\/mol<br>\u2248 351.93 mol of C\u2082F\u2084<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Step 3: Determine the moles of fluorine atoms<\/strong><\/p>\n\n\n\n<p>Each molecule of C\u2082F\u2084 contains 4 fluorine atoms. So,<\/p>\n\n\n\n<p>Moles of fluorine atoms = 351.93 mol C\u2082F\u2084 \u00d7 4<br>= 1,407.72 mol of fluorine atoms<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Step 4: Convert moles of fluorine atoms to grams<\/strong><\/p>\n\n\n\n<p>Atomic mass of fluorine = 18.998 g\/mol<\/p>\n\n\n\n<p>Mass of fluorine = 1,407.72 mol \u00d7 18.998 g\/mol<br>\u2248 <strong>26,729 g of fluorine<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Final Answer: <strong>26,729 grams of fluorine<\/strong><\/h3>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p>This problem involves using dimensional analysis and mole-to-atom relationships to determine the mass of a specific element within a compound. The compound in question is C\u2082F\u2084, also known as tetrafluoroethylene. The molecular formula tells us that each molecule consists of two carbon atoms and four fluorine atoms. The molar mass of this compound is given as 100.02 g\/mol, which is the mass of one mole of C\u2082F\u2084 molecules.<\/p>\n\n\n\n<p>We start by converting the given mass of C\u2082F\u2084 from kilograms to grams, because the molar mass is given in grams per mole. This gives us 35,200 grams of C\u2082F\u2084. Next, we calculate how many moles of C\u2082F\u2084 are present by dividing the total mass by the molar mass. This gives approximately 351.93 moles of C\u2082F\u2084.<\/p>\n\n\n\n<p>Since each mole of C\u2082F\u2084 contains four moles of fluorine atoms, we multiply 351.93 by 4 to get 1,407.72 moles of fluorine atoms. To find the total mass of fluorine, we multiply the number of moles of fluorine by the atomic mass of a single fluorine atom, which is 18.998 grams per mole. This yields approximately 26,729 grams of fluorine.<\/p>\n\n\n\n<p>This approach is standard in stoichiometric calculations and relies on understanding molar relationships within compounds. It is critical in chemical analysis, especially when determining the elemental composition of substances in large quantities.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1174.jpeg\" alt=\"\" class=\"wp-image-39651\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1174.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1174-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1174-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>How many grams of fluorine are in 35.2 kg of C2F4 (molar mass = 100.02 g\/mol)? The Correct Answer and Explanation is: To find how many grams of fluorine are in 35.2 kg of C\u2082F\u2084, follow these steps: Step 1: Convert kilograms of C\u2082F\u2084 to grams 35.2 kg \u00d7 1,000 g\/kg = 35,200 g of [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-39649","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/39649","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=39649"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/39649\/revisions"}],"predecessor-version":[{"id":39652,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/39649\/revisions\/39652"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=39649"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=39649"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=39649"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}