{"id":39447,"date":"2025-06-27T07:36:16","date_gmt":"2025-06-27T07:36:16","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=39447"},"modified":"2025-06-27T07:36:17","modified_gmt":"2025-06-27T07:36:17","slug":"if-a-rx-has-delta-s-positive-and-delta-h-negative-the-rx-is","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/if-a-rx-has-delta-s-positive-and-delta-h-negative-the-rx-is\/","title":{"rendered":"If a rx has delta S positive and delta H negative, the rx is"},"content":{"rendered":"\n<p>If a rx has delta S positive and delta H negative, the rx is <\/p>\n\n\n\n<p>A. non-spontaneous at all temp <\/p>\n\n\n\n<p>B. spontaneous at all temp <\/p>\n\n\n\n<p>C. spontaneous only at high temp <\/p>\n\n\n\n<p>D. spontaneous only at low temp<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Correct Answer: B. spontaneous at all temp<\/strong><\/p>\n\n\n\n<p>To determine the spontaneity of a chemical reaction, we use the Gibbs free energy change (\u0394G), which is given by the equation:<\/p>\n\n\n\n<p><strong>\u0394G = \u0394H \u2013 T\u0394S<\/strong><\/p>\n\n\n\n<p>Where:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>\u0394G is the change in Gibbs free energy<\/li>\n\n\n\n<li>\u0394H is the change in enthalpy<\/li>\n\n\n\n<li>T is the temperature in Kelvin<\/li>\n\n\n\n<li>\u0394S is the change in entropy<\/li>\n<\/ul>\n\n\n\n<p>A reaction is <strong>spontaneous<\/strong> when \u0394G is <strong>negative<\/strong>. Now, consider the signs given in the question:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>\u0394H is <strong>negative<\/strong> (this means the reaction is <strong>exothermic<\/strong>)<\/li>\n\n\n\n<li>\u0394S is <strong>positive<\/strong> (this means the reaction leads to an <strong>increase in disorder<\/strong>)<\/li>\n<\/ul>\n\n\n\n<p>Plugging these values into the Gibbs free energy equation:<\/p>\n\n\n\n<p>\u0394G = (negative number) \u2013 T \u00d7 (positive number)<\/p>\n\n\n\n<p>Since T is always a positive value in Kelvin, the term T\u0394S will also be positive. Subtracting a positive value from a negative \u0394H makes \u0394G even more negative. In other words, both terms (\u0394H and \u2013T\u0394S) contribute to making \u0394G negative.<\/p>\n\n\n\n<p>This means that regardless of the temperature, the reaction will always have a negative \u0394G. Therefore, it will be spontaneous at <strong>all temperatures<\/strong>.<\/p>\n\n\n\n<p>This type of situation represents the most favorable thermodynamic condition for a reaction to occur. A negative \u0394H indicates that the reaction releases energy, while a positive \u0394S suggests that the disorder of the system increases. Both of these are characteristics that favor spontaneity.<\/p>\n\n\n\n<p>In summary, when a reaction has a negative \u0394H and a positive \u0394S, it will always result in a negative \u0394G. This ensures that the reaction is spontaneous no matter the temperature. Therefore, the correct choice is <strong>B. spontaneous at all temp<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>If a rx has delta S positive and delta H negative, the rx is A. non-spontaneous at all temp B. spontaneous at all temp C. spontaneous only at high temp D. spontaneous only at low temp The correct answer and explanation is: Correct Answer: B. spontaneous at all temp To determine the spontaneity of a [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-39447","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/39447","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=39447"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/39447\/revisions"}],"predecessor-version":[{"id":39448,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/39447\/revisions\/39448"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=39447"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=39447"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=39447"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}