{"id":39064,"date":"2025-06-26T18:50:04","date_gmt":"2025-06-26T18:50:04","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=39064"},"modified":"2025-06-26T18:50:05","modified_gmt":"2025-06-26T18:50:05","slug":"how-many-c2h4-molecules-are-contained-in-45-8-mg-of-c2h4","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/how-many-c2h4-molecules-are-contained-in-45-8-mg-of-c2h4\/","title":{"rendered":"How many C2H4 molecules are contained in 45.8 mg of C2H4"},"content":{"rendered":"\n

How many C2H4 molecules are contained in 45.8 mg of C2H4? The molar mass of C2H4 is 28.05 g\/mol. A) 9.83 \\times 10^{20} C2H4 molecules B) 2.71 \\times 10^{20} C2H4 molecules C) 7.74 \\times 10^{26} C2H4 molecules D) 3.69 \\times 10^{23} C2H4 molecules E) 4.69 \\times 10^{23} C2H4 molecules<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

To determine how many C\u2082H\u2084 molecules are present in 45.8 mg of C\u2082H\u2084, follow these steps:<\/p>\n\n\n\n

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Step 1: Convert milligrams to grams<\/strong><\/h3>\n\n\n\n

Since the molar mass is in grams per mole, convert 45.8 mg to grams:45.8\u2009mg=45.81000=0.0458\u2009g45.8\\, \\text{mg} = \\frac{45.8}{1000} = 0.0458\\, \\text{g}45.8mg=100045.8\u200b=0.0458g<\/p>\n\n\n\n

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Step 2: Calculate number of moles<\/strong><\/h3>\n\n\n\n

Use the molar mass of C\u2082H\u2084 (28.05 g\/mol) to calculate moles:Moles of C2H4=0.0458\u2009g28.05\u2009g\/mol=0.001633\u2009mol\\text{Moles of } C_2H_4 = \\frac{0.0458\\, \\text{g}}{28.05\\, \\text{g\/mol}} = 0.001633\\, \\text{mol}Moles of C2\u200bH4\u200b=28.05g\/mol0.0458g\u200b=0.001633mol<\/p>\n\n\n\n

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Step 3: Convert moles to molecules<\/strong><\/h3>\n\n\n\n

Use Avogadro\u2019s number, which is:6.022\u00d71023\u2009molecules\/mol6.022 \\times 10^{23}\\, \\text{molecules\/mol}6.022\u00d71023molecules\/molMolecules of C2H4=0.001633\u2009mol\u00d76.022\u00d71023\u2009molecules\/mol\\text{Molecules of } C_2H_4 = 0.001633\\, \\text{mol} \\times 6.022 \\times 10^{23}\\, \\text{molecules\/mol}Molecules of C2\u200bH4\u200b=0.001633mol\u00d76.022\u00d71023molecules\/mol=9.83\u00d71020\u2009molecules= 9.83 \\times 10^{20}\\, \\text{molecules}=9.83\u00d71020molecules<\/p>\n\n\n\n

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Answer: A) 9.83\u00d710209.83 \\times 10^{20}9.83\u00d71020 C\u2082H\u2084 molecules<\/strong><\/h3>\n\n\n\n
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Explanation<\/strong><\/h3>\n\n\n\n

To find the number of ethene (C\u2082H\u2084) molecules in a given mass, we first need to understand the relationship between mass, moles, and the number of molecules. The concept of the mole is central in chemistry. A mole represents a specific number of particles, known as Avogadro\u2019s number, which is 6.022\u00d710236.022 \\times 10^{23}6.022\u00d71023. The molar mass of a substance tells us how much one mole of that substance weighs. For C\u2082H\u2084, the molar mass is 28.05 g\/mol, which means one mole of ethene weighs 28.05 grams.<\/p>\n\n\n\n

Since the question gives the mass of ethene in milligrams, we start by converting it to grams because molar mass is expressed in grams per mole. After converting 45.8 mg to 0.0458 g, we divide this mass by the molar mass to determine how many moles are present. This gives us approximately 0.001633 moles of C\u2082H\u2084.<\/p>\n\n\n\n

To find how many molecules this represents, we multiply the number of moles by Avogadro\u2019s number. This multiplication gives us approximately 9.83\u00d710209.83 \\times 10^{20}9.83\u00d71020 molecules of ethene. This process shows the importance of unit conversions and the concept of the mole in linking the macroscopic measurement of mass to the microscopic count of individual molecules.<\/p>\n\n\n\n

Thus, the correct answer is A<\/strong>.<\/p>\n\n\n\n

\"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

How many C2H4 molecules are contained in 45.8 mg of C2H4? The molar mass of C2H4 is 28.05 g\/mol. A) 9.83 \\times 10^{20} C2H4 molecules B) 2.71 \\times 10^{20} C2H4 molecules C) 7.74 \\times 10^{26} C2H4 molecules D) 3.69 \\times 10^{23} C2H4 molecules E) 4.69 \\times 10^{23} C2H4 molecules The Correct Answer and Explanation is: […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-39064","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/39064","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=39064"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/39064\/revisions"}],"predecessor-version":[{"id":39066,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/39064\/revisions\/39066"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=39064"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=39064"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=39064"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}