{"id":38968,"date":"2025-06-26T16:20:31","date_gmt":"2025-06-26T16:20:31","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=38968"},"modified":"2025-06-26T16:20:32","modified_gmt":"2025-06-26T16:20:32","slug":"what-is-the-pka-of-sodium-ethoxide","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/what-is-the-pka-of-sodium-ethoxide\/","title":{"rendered":"What is the pKa of sodium ethoxide"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">What is the pKa of sodium ethoxide?<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Correct Answer:<\/strong> The pKa of sodium ethoxide (specifically, the conjugate acid ethanol) is approximately <strong>16<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Sodium ethoxide (NaOCH\u2082CH\u2083) is the sodium salt of ethanol. It is a <strong>strong base<\/strong> commonly used in organic chemistry, especially in elimination (E2) and condensation reactions. However, when we talk about the pKa of sodium ethoxide, we are actually referring to the <strong>pKa of its conjugate acid<\/strong>, which is <strong>ethanol (CH\u2083CH\u2082OH)<\/strong>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">The pKa of ethanol is about <strong>16<\/strong>, meaning that ethanol is a weak acid. This also tells us something important about sodium ethoxide: since its conjugate acid has a high pKa value, sodium ethoxide itself is a strong base. In acid-base chemistry, a <strong>high pKa means a weak acid<\/strong>, and therefore, its conjugate base (in this case, ethoxide ion) must be relatively strong.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">To understand this better, consider the equilibrium:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>CH\u2083CH\u2082OH \u21cc CH\u2083CH\u2082O\u207b + H\u207a<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">This equilibrium lies far to the left because ethanol does not give up its proton easily. As a result, its conjugate base, ethoxide ion (CH\u2083CH\u2082O\u207b), has a strong tendency to grab protons, making it a good base.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Sodium ethoxide exists as a salt: <strong>Na\u207a CH\u2083CH\u2082O\u207b<\/strong>. The sodium ion does not directly influence the acidity or basicity of the compound; it simply balances the charge of the ethoxide ion. What makes sodium ethoxide useful is the ethoxide ion\u2019s reactivity.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">In summary, the <strong>pKa of sodium ethoxide<\/strong> refers to the <strong>pKa of ethanol<\/strong>, which is <strong>about 16<\/strong>. This value tells us that sodium ethoxide is a <strong>strong base<\/strong>, suitable for many types of deprotonation reactions in organic synthesis.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1101.jpeg\" alt=\"\" class=\"wp-image-38979\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1101.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1101-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1101-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>What is the pKa of sodium ethoxide? The Correct Answer and Explanation is: Correct Answer: The pKa of sodium ethoxide (specifically, the conjugate acid ethanol) is approximately 16. Explanation: Sodium ethoxide (NaOCH\u2082CH\u2083) is the sodium salt of ethanol. It is a strong base commonly used in organic chemistry, especially in elimination (E2) and condensation reactions. [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-38968","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/38968","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=38968"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/38968\/revisions"}],"predecessor-version":[{"id":38980,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/38968\/revisions\/38980"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=38968"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=38968"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=38968"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}