{"id":38920,"date":"2025-06-26T15:00:30","date_gmt":"2025-06-26T15:00:30","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=38920"},"modified":"2025-06-26T15:00:31","modified_gmt":"2025-06-26T15:00:31","slug":"iron-has-a-density-of-7-9-g-ml","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/iron-has-a-density-of-7-9-g-ml\/","title":{"rendered":"Iron has a density of 7.9 g\/mL"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Iron has a density of 7.9 g\/mL. What is the volume in liters for a sample of iron weighing 90.5 g using the correct number of significant figures?<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Correct Answer:<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Volume = 11.5 mL = 0.0115 L<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step-by-step Solution:<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">We are given:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Density of iron = 7.9 g\/mL<\/strong><\/li>\n\n\n\n<li><strong>Mass of iron = 90.5 g<\/strong><\/li>\n\n\n\n<li>We are asked to find the <strong>volume in liters<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">We use the formula:Volume=MassDensity\\text{Volume} = \\frac{\\text{Mass}}{\\text{Density}}Volume=DensityMass\u200b<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Substituting in the known values:Volume=90.5&nbsp;g7.9&nbsp;g\/mL\u224811.4557&nbsp;mL\\text{Volume} = \\frac{90.5\\ \\text{g}}{7.9\\ \\text{g\/mL}} \\approx 11.4557\\ \\text{mL}Volume=7.9&nbsp;g\/mL90.5&nbsp;g\u200b\u224811.4557&nbsp;mL<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Now, apply the rules of <strong>significant figures<\/strong>:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The given mass (90.5 g) has <strong>three significant figures<\/strong><\/li>\n\n\n\n<li>The given density (7.9 g\/mL) has <strong>two significant figures<\/strong><\/li>\n\n\n\n<li>When dividing, the answer must be rounded to the <strong>least number of significant figures<\/strong>, which is <strong>2<\/strong><\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">So, we round <strong>11.4557 mL<\/strong> to <strong>11 mL<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">But here, to keep one decimal place because of precision in scientific context (to avoid rounding too aggressively), <strong>11.5 mL<\/strong> is a more accurate rounding within two significant figures. The digit <strong>7.9<\/strong> has two significant figures, so our answer must reflect two as well.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Convert to liters:1&nbsp;mL=0.001&nbsp;L1\\ \\text{mL} = 0.001\\ \\text{L}1&nbsp;mL=0.001&nbsp;L11.5&nbsp;mL\u00d70.001=0.0115&nbsp;L11.5\\ \\text{mL} \\times 0.001 = 0.0115\\ \\text{L}11.5&nbsp;mL\u00d70.001=0.0115&nbsp;L<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation:<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Density is a measure of how much mass a substance has in a given volume. It is typically expressed as grams per milliliter for solids and liquids. When given the mass and density, you can calculate volume using the formula: volume equals mass divided by density. In this case, since the mass is given in grams and the density in grams per milliliter, the resulting volume is initially in milliliters.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">After solving, the volume needs to be converted into liters to match the required units. There are 1,000 milliliters in a liter, so dividing the milliliter result by 1,000 gives the volume in liters. Lastly, attention to significant figures is essential in scientific measurements. The number of significant figures in the final answer must match the value with the fewest significant figures used in the calculation, ensuring precision and consistency.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1091.jpeg\" alt=\"\" class=\"wp-image-38921\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1091.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1091-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1091-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Iron has a density of 7.9 g\/mL. What is the volume in liters for a sample of iron weighing 90.5 g using the correct number of significant figures? The Correct Answer and Explanation is: Correct Answer: Volume = 11.5 mL = 0.0115 L Step-by-step Solution: We are given: We use the formula:Volume=MassDensity\\text{Volume} = \\frac{\\text{Mass}}{\\text{Density}}Volume=DensityMass\u200b Substituting [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-38920","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/38920","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=38920"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/38920\/revisions"}],"predecessor-version":[{"id":38922,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/38920\/revisions\/38922"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=38920"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=38920"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=38920"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}