{"id":38858,"date":"2025-06-26T15:56:40","date_gmt":"2025-06-26T15:56:40","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=38858"},"modified":"2025-06-26T15:56:42","modified_gmt":"2025-06-26T15:56:42","slug":"how-many-grams-of-sulfur-dioxide-are-present-in-2-29-moles-of-this-compound","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/how-many-grams-of-sulfur-dioxide-are-present-in-2-29-moles-of-this-compound\/","title":{"rendered":"How many grams of sulfur dioxide are present in 2.29 moles of this compound"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">How many grams of sulfur dioxide are present in 2.29 moles of this compound?<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">To find the number of grams of sulfur dioxide (SO\u2082) in 2.29 moles, use the formula:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Mass (g) = Moles \u00d7 Molar Mass<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">The molar mass of sulfur dioxide (SO\u2082) is calculated by adding the atomic masses of its elements:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Sulfur (S) = 32.07 g\/mol<\/li>\n\n\n\n<li>Oxygen (O) = 16.00 g\/mol<\/li>\n\n\n\n<li>SO\u2082 has 1 sulfur atom and 2 oxygen atoms<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">So:<br><strong>Molar mass of SO\u2082 = 32.07 + (2 \u00d7 16.00) = 32.07 + 32.00 = 64.07 g\/mol<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Now multiply:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Mass = 2.29 mol \u00d7 64.07 g\/mol = 146.72 grams<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Final Answer: <strong>146.72 grams<\/strong><\/h3>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">To convert from moles to grams, it is necessary to use the concept of molar mass. A mole is a unit used to count particles such as atoms or molecules. In this case, the compound is sulfur dioxide (SO\u2082), a molecule consisting of one sulfur atom and two oxygen atoms.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">The molar mass acts like a conversion factor between moles and grams. Every substance has a unique molar mass based on its chemical composition. For sulfur dioxide, adding the atomic masses of one sulfur atom and two oxygen atoms gives a molar mass of 64.07 grams per mole. This means one mole of SO\u2082 weighs 64.07 grams.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">To find out how much 2.29 moles of SO\u2082 weigh, multiply the number of moles by the molar mass. This yields 146.72 grams. The result indicates the total mass of SO\u2082 present in 2.29 moles of the compound. This approach is standard in chemistry and helps convert between the measurable amount in grams and the chemical quantity in moles. This type of calculation is essential for preparing solutions, performing reactions, and analyzing substances in chemical studies.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>How many grams of sulfur dioxide are present in 2.29 moles of this compound? The correct answer and explanation is: To find the number of grams of sulfur dioxide (SO\u2082) in 2.29 moles, use the formula: Mass (g) = Moles \u00d7 Molar Mass The molar mass of sulfur dioxide (SO\u2082) is calculated by adding the [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-38858","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/38858","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=38858"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/38858\/revisions"}],"predecessor-version":[{"id":38955,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/38858\/revisions\/38955"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=38858"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=38858"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=38858"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}