{"id":38611,"date":"2025-06-26T10:58:14","date_gmt":"2025-06-26T10:58:14","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=38611"},"modified":"2025-06-26T10:58:16","modified_gmt":"2025-06-26T10:58:16","slug":"what-is-the-molarity-of-fe2-ions-in-an-aqueous-solution-with-a-volume-of-450-ml-that-contains-200-g-of-iron-ii-chloride-fecl2","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/what-is-the-molarity-of-fe2-ions-in-an-aqueous-solution-with-a-volume-of-450-ml-that-contains-200-g-of-iron-ii-chloride-fecl2\/","title":{"rendered":"What is the molarity of Fe2+ ions in an aqueous solution with a volume of 450.mL that contains 200. g of iron (II) chloride, FeCl2?"},"content":{"rendered":"\n<p>What is the molarity of Fe2+ ions in an aqueous solution with a volume of 450.mL that contains 200. g of iron (II) chloride, FeCl2?<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To calculate the <strong>molarity (M)<\/strong> of Fe\u00b2\u207a ions in the solution, follow these steps:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 1: Write the chemical formula and dissociation<\/strong><\/h3>\n\n\n\n<p>Iron(II) chloride (FeCl\u2082) dissolves in water as follows: FeCl2(s)\u2192Fe2+(aq)+2Cl\u2212(aq)\\text{FeCl}_2 (s) \\rightarrow \\text{Fe}^{2+} (aq) + 2\\text{Cl}^{-} (aq)FeCl2\u200b(s)\u2192Fe2+(aq)+2Cl\u2212(aq)<\/p>\n\n\n\n<p>From this equation, <strong>1 mole of FeCl\u2082 produces 1 mole of Fe\u00b2\u207a ions<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 2: Calculate molar mass of FeCl\u2082<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Fe: 55.85 g\/mol<\/li>\n\n\n\n<li>Cl: 35.45 g\/mol \u00d7 2 = 70.90 g\/mol<\/li>\n\n\n\n<li><strong>Molar mass of FeCl\u2082 = 55.85 + 70.90 = 126.75 g\/mol<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 3: Convert mass to moles<\/strong><\/h3>\n\n\n\n<p>You are given <strong>200. g of FeCl\u2082<\/strong>, so: Moles&nbsp;of&nbsp;FeCl2=200.&nbsp;g126.75&nbsp;g\/mol\u22481.578&nbsp;mol\\text{Moles of FeCl}_2 = \\frac{200. \\text{ g}}{126.75 \\text{ g\/mol}} \\approx 1.578 \\text{ mol}Moles&nbsp;of&nbsp;FeCl2\u200b=126.75&nbsp;g\/mol200.&nbsp;g\u200b\u22481.578&nbsp;mol<\/p>\n\n\n\n<p>Since 1 mole of FeCl\u2082 yields 1 mole of Fe\u00b2\u207a: Moles&nbsp;of&nbsp;Fe2+=1.578&nbsp;mol\\text{Moles of Fe}^{2+} = 1.578 \\text{ mol}Moles&nbsp;of&nbsp;Fe2+=1.578&nbsp;mol<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 4: Convert volume from mL to L<\/strong><\/h3>\n\n\n\n<p>450.&nbsp;mL=0.450&nbsp;L450. \\text{ mL} = 0.450 \\text{ L}450.&nbsp;mL=0.450&nbsp;L<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 5: Calculate molarity<\/strong><\/h3>\n\n\n\n<p>Molarity&nbsp;(M)=moles&nbsp;of&nbsp;soluteliters&nbsp;of&nbsp;solution=1.5780.450\u22483.51\u2009M\\text{Molarity (M)} = \\frac{\\text{moles of solute}}{\\text{liters of solution}} = \\frac{1.578}{0.450} \\approx \\boxed{3.51 \\, \\text{M}}Molarity&nbsp;(M)=liters&nbsp;of&nbsp;solutionmoles&nbsp;of&nbsp;solute\u200b=0.4501.578\u200b\u22483.51M\u200b<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 <strong>Final Answer:<\/strong><\/h3>\n\n\n\n<p>The molarity of Fe\u00b2\u207a ions in the solution is <strong>3.51 M<\/strong>.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1044.jpeg\" alt=\"\" class=\"wp-image-38612\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1044.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1044-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-1044-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>What is the molarity of Fe2+ ions in an aqueous solution with a volume of 450.mL that contains 200. g of iron (II) chloride, FeCl2? The Correct Answer and Explanation is: To calculate the molarity (M) of Fe\u00b2\u207a ions in the solution, follow these steps: Step 1: Write the chemical formula and dissociation Iron(II) chloride [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-38611","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/38611","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=38611"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/38611\/revisions"}],"predecessor-version":[{"id":38613,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/38611\/revisions\/38613"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=38611"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=38611"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=38611"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}