{"id":38479,"date":"2025-06-26T10:04:34","date_gmt":"2025-06-26T10:04:34","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=38479"},"modified":"2025-06-26T10:04:36","modified_gmt":"2025-06-26T10:04:36","slug":"caoh2-h2so4-%ef%82%ae-caso4-h2o","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/caoh2-h2so4-%ef%82%ae-caso4-h2o\/","title":{"rendered":"Ca(OH)2 + H2SO4 \uf0ae CaSO4 + H2O"},"content":{"rendered":"\n

. Ca(OH)2 + H2SO4 \uf0ae CaSO4 + H2O a) How many grams (g) of H2SO4 are needed to react with 40 grams of Ca(OH)2? b) How much CaSO4 (in grams) will be formed? c) How much H2O (in grams) will be formed?<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

To solve this problem, we need to follow stoichiometric steps based on the balanced chemical equation:<\/p>\n\n\n\n

Balanced equation:<\/strong>Ca(OH)2+H2SO4\u2192CaSO4+2H2O\\text{Ca(OH)}_2 + \\text{H}_2\\text{SO}_4 \\rightarrow \\text{CaSO}_4 + 2\\text{H}_2\\text{O}Ca(OH)2\u200b+H2\u200bSO4\u200b\u2192CaSO4\u200b+2H2\u200bO<\/p>\n\n\n\n

\n\n\n\n

Step-by-step Solutions:<\/h3>\n\n\n\n

Step 1: Molar masses (g\/mol)<\/strong><\/p>\n\n\n\n

    \n
  • Ca(OH)\u2082 = 40.08 (Ca) + 2\u00d7(16.00 + 1.01) = 74.10 g\/mol<\/li>\n\n\n\n
  • H\u2082SO\u2084 = 2\u00d71.01 + 32.07 + 4\u00d716.00 = 98.09 g\/mol<\/li>\n\n\n\n
  • CaSO\u2084 = 40.08 + 32.07 + 4\u00d716.00 = 136.15 g\/mol<\/li>\n\n\n\n
  • H\u2082O = 2\u00d71.01 + 16.00 = 18.02 g\/mol<\/li>\n<\/ul>\n\n\n\n
    \n\n\n\n

    a) How many grams of H\u2082SO\u2084 are needed to react with 40 grams of Ca(OH)\u2082?<\/h3>\n\n\n\n

    Step 1:<\/strong> Find moles of Ca(OH)\u2082:40.00 g74.10 g\/mol\u22480.54 mol\\frac{40.00\\ \\text{g}}{74.10\\ \\text{g\/mol}} \\approx 0.54\\ \\text{mol}74.10 g\/mol40.00 g\u200b\u22480.54 mol<\/p>\n\n\n\n

    Step 2:<\/strong> Use the mole ratio (1:1) from the balanced equation:0.54 mol of Ca(OH)2 reactswith 0.54 mol of H2SO40.54\\ \\text{mol of Ca(OH)}_2\\ reacts with\\ 0.54\\ \\text{mol of H}_2\\text{SO}_40.54 mol of Ca(OH)2\u200b reactswith 0.54 mol of H2\u200bSO4\u200b<\/p>\n\n\n\n

    Step 3:<\/strong> Convert to grams:0.54 mol\u00d798.09 g\/mol\u224852.97 g0.54\\ \\text{mol} \\times 98.09\\ \\text{g\/mol} \\approx 52.97\\ \\text{g}0.54 mol\u00d798.09 g\/mol\u224852.97 g<\/p>\n\n\n\n

    Answer:<\/strong> 52.97 grams of H\u2082SO\u2084<\/strong><\/p>\n\n\n\n

    \n\n\n\n

    b) How much CaSO\u2084 (in grams) will be formed?<\/h3>\n\n\n\n

    Mole ratio of Ca(OH)\u2082 to CaSO\u2084 is 1:1<\/strong>, so 0.54 mol of CaSO\u2084 is formed.0.54 mol\u00d7136.15 g\/mol\u224873.52 g0.54\\ \\text{mol} \\times 136.15\\ \\text{g\/mol} \\approx 73.52\\ \\text{g}0.54 mol\u00d7136.15 g\/mol\u224873.52 g<\/p>\n\n\n\n

    Answer:<\/strong> 73.52 grams of CaSO\u2084<\/strong><\/p>\n\n\n\n

    \n\n\n\n

    c) How much H\u2082O (in grams) will be formed?<\/h3>\n\n\n\n

    From the balanced equation, 1 mol of Ca(OH)\u2082 makes 2 mol of H\u2082O<\/strong>0.54 mol Ca(OH)2\u00d72=1.08 mol H2O0.54\\ \\text{mol Ca(OH)}_2 \\times 2 = 1.08\\ \\text{mol H}_2\\text{O}0.54 mol Ca(OH)2\u200b\u00d72=1.08 mol H2\u200bO1.08 mol\u00d718.02 g\/mol\u224819.46 g1.08\\ \\text{mol} \\times 18.02\\ \\text{g\/mol} \\approx 19.46\\ \\text{g}1.08 mol\u00d718.02 g\/mol\u224819.46 g<\/p>\n\n\n\n

    Answer:<\/strong> 19.46 grams of H\u2082O<\/strong><\/p>\n\n\n\n

    \n\n\n\n

    Explanation:<\/h3>\n\n\n\n

    This problem demonstrates stoichiometry, which is the calculation of reactants and products in chemical reactions. The equation tells us the mole relationships between substances. We use molar mass to convert grams to moles, apply mole ratios from the balanced equation, and convert moles of products or other reactants back to grams. Here, the 1:1 mole ratios between Ca(OH)\u2082, H\u2082SO\u2084, and CaSO\u2084 simplify the calculations. The only exception is H\u2082O, which has a 2:1 ratio with Ca(OH)\u2082, giving us twice as many moles of water per mole of base.<\/p>\n\n\n\n

    \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

    . Ca(OH)2 + H2SO4 \uf0ae CaSO4 + H2O a) How many grams (g) of H2SO4 are needed to react with 40 grams of Ca(OH)2? b) How much CaSO4 (in grams) will be formed? c) How much H2O (in grams) will be formed? The Correct Answer and Explanation is: To solve this problem, we need to […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-38479","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/38479","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=38479"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/38479\/revisions"}],"predecessor-version":[{"id":38485,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/38479\/revisions\/38485"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=38479"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=38479"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=38479"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}