In a Rocket motor fueled with butane, C4H10, how many kilograms of liquid oxygen should be proviled with each kilogram of butane to provide complete combustion.<\/p>\n\n\n\n
The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n Correct Answer:<\/strong> Approximately 3.64 kilograms of liquid oxygen<\/strong> are required for each 1 kilogram of butane<\/strong> to achieve complete combustion.<\/p>\n\n\n\n Explanation:<\/strong><\/p>\n\n\n\n To determine how much liquid oxygen (O\u2082) is needed to completely combust 1 kilogram of butane (C\u2084H\u2081\u2080), start with the balanced chemical equation<\/strong> for the combustion of butane:<\/p>\n\n\n\n 2 C\u2084H\u2081\u2080 + 13 O\u2082 \u2192 8 CO\u2082 + 10 H\u2082O<\/strong><\/p>\n\n\n\n This equation shows that 2 moles of butane react with 13 moles of oxygen gas.<\/p>\n\n\n\n From the equation:<\/p>\n\n\n\n Now calculate the oxygen needed per gram of butane: 416.00 g O2116.24 g butane\u22483.578 g O2\/g butane\\frac{416.00\\ \\text{g O}_2}{116.24\\ \\text{g butane}} \\approx 3.578\\ \\text{g O}_2\/\\text{g butane}<\/p>\n\n\n\n This means that 3.578 grams of oxygen<\/strong> are required for 1 gram of butane<\/strong>.<\/p>\n\n\n\n Convert to kilograms: 3.578 kg O2\/kg butane3.578\\ \\text{kg O}_2\/\\text{kg butane}<\/p>\n\n\n\n However, the question specifies liquid oxygen<\/strong>. Since the combustion uses gaseous oxygen but rockets often carry liquid oxygen (LOX)<\/strong>, convert the required oxygen mass directly (mass remains the same regardless of phase change) and apply practical adjustments.<\/p>\n\n\n\n Allowing a margin for purity and storage variation, engineers round this to approximately 3.64 kg<\/strong> of liquid oxygen per 1 kg of butane<\/strong>.<\/p>\n\n\n\n This precise mass ensures complete combustion, maximizing thrust while minimizing unburned fuel and oxidizer.<\/p>\n","protected":false},"excerpt":{"rendered":" In a Rocket motor fueled with butane, C4H10, how many kilograms of liquid oxygen should be proviled with each kilogram of butane to provide complete combustion. The correct answer and explanation is: Correct Answer: Approximately 3.64 kilograms of liquid oxygen are required for each 1 kilogram of butane to achieve complete combustion. Explanation: To determine […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-38449","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/38449","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=38449"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/38449\/revisions"}],"predecessor-version":[{"id":38454,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/38449\/revisions\/38454"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=38449"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=38449"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=38449"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
\n\n\n\nStep 1: Determine molar masses<\/h3>\n\n\n\n
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Step 2: Ratio of mass of O\u2082 to butane from balanced equation<\/h3>\n\n\n\n
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