Correct Answer:<\/strong> Explanation:<\/strong> 1. Tin(IV) Ion (Sn\u2074\u207a):<\/strong> 2. Phosphate Ion (PO\u2084\u00b3\u207b):<\/strong> 3. Balancing Charges:<\/strong> To balance:<\/p>\n\n\n\n Let us determine the least common multiple (LCM)<\/strong> of 4 and 3, which is 12<\/strong>. This means we need 12 positive charges and 12 negative charges to balance.<\/p>\n\n\n\n To get +12 charge: To get \u221212 charge: 4. Final Formula:<\/strong> 5. Naming:<\/strong> Understanding how to write chemical formulas requires knowledge of ion charges and how to balance them. This ensures the compound is electrically neutral, which is a fundamental principle in forming ionic compounds.<\/p>\n\n\n\n What is the formula of tin(IV) phosphate? The Correct Answer and Explanation is: Correct Answer:The formula of tin(IV) phosphate is Sn\u2083(PO\u2084)\u2084. Explanation:To determine the correct formula of tin(IV) phosphate, we first need to understand the charges of the ions involved. 1. Tin(IV) Ion (Sn\u2074\u207a):The Roman numeral IV indicates that the tin ion has a +4 […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-38028","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/38028","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=38028"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/38028\/revisions"}],"predecessor-version":[{"id":38030,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/38028\/revisions\/38030"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=38028"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=38028"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=38028"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
The formula of tin(IV) phosphate is Sn\u2083(PO\u2084)\u2084<\/strong>.<\/p>\n\n\n\n
\n\n\n\n
To determine the correct formula of tin(IV) phosphate, we first need to understand the charges of the ions involved.<\/p>\n\n\n\n
The Roman numeral IV indicates that the tin ion has a +4 charge<\/strong>. This means that each tin ion will contribute four positive charges to the compound.<\/p>\n\n\n\n
The phosphate ion is a polyatomic ion<\/strong> with a \u22123 charge<\/strong>. It contains one phosphorus atom and four oxygen atoms, and as a group, it carries three negative charges.<\/p>\n\n\n\n
In an ionic compound, the total positive charge must balance the total negative charge. We need to find the smallest whole number ratio<\/strong> of Sn\u2074\u207a and PO\u2084\u00b3\u207b ions so that the overall charge of the compound is zero.<\/p>\n\n\n\n\n
We need 3 Sn\u2074\u207a ions<\/strong> (3 \u00d7 +4 = +12).<\/p>\n\n\n\n
We need 4 PO\u2084\u00b3\u207b ions<\/strong> (4 \u00d7 \u22123 = \u221212).<\/p>\n\n\n\n
Combining 3 Sn\u2074\u207a ions and 4 PO\u2084\u00b3\u207b ions gives the formula:
Sn\u2083(PO\u2084)\u2084<\/strong><\/p>\n\n\n\n
This compound is named tin(IV) phosphate<\/strong> because tin is in the +4 oxidation state, and the anion is phosphate.<\/p>\n\n\n\n![\"\"](\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-999.jpeg\")
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