{"id":37617,"date":"2025-06-26T03:21:40","date_gmt":"2025-06-26T03:21:40","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=37617"},"modified":"2025-06-26T03:21:41","modified_gmt":"2025-06-26T03:21:41","slug":"the-combustion-reaction-for-propane","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/the-combustion-reaction-for-propane\/","title":{"rendered":"\u00a0The combustion reaction for propane"},"content":{"rendered":"\n<pre id=\"preorder-ask-header-text\" class=\"wp-block-preformatted\">&nbsp;The combustion reaction for propane<\/pre>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"359\" height=\"601\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/image-338.png\" alt=\"\" class=\"wp-image-37618\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/image-338.png 359w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/image-338-179x300.png 179w\" sizes=\"auto, (max-width: 359px) 100vw, 359px\" \/><\/figure>\n\n\n\n<p>The Correct Answer and Explanation is:<\/p>\n\n\n\n<p>Here are the correct answers followed by a detailed explanation:<\/p>\n\n\n\n<p><strong>Question 6 Answer: C. 5 moles of O\u2082 are required<\/strong> <strong>Question 7 Answer: C. N\u2082 + 3 H\u2082 \u2192 2 NH\u2083<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p>For Question 6, we are analyzing the complete combustion of propane, which is represented by the balanced equation:<\/p>\n\n\n\n<p>C\u2083H\u2088 (g) + 5 O\u2082 (g) \u2192 3 CO\u2082 (g) + 4 H\u2082O (l)<\/p>\n\n\n\n<p>The coefficients in this chemical equation provide the molar ratios. They indicate that one mole of propane (C\u2083H\u2088) reacts with five moles of oxygen gas (O\u2082) to produce three moles of carbon dioxide (CO\u2082) and four moles of water (H\u2082O). This reaction exemplifies a typical combustion process, which involves a hydrocarbon reacting with oxygen to form carbon dioxide and water. Therefore, the correct number of moles of oxygen required to completely combust one mole of propane is five. Option C correctly reflects this stoichiometric ratio.<\/p>\n\n\n\n<p>For Question 7, we are identifying the only correctly balanced chemical equation. Option C:<\/p>\n\n\n\n<p>N\u2082 + 3 H\u2082 \u2192 2 NH\u2083<\/p>\n\n\n\n<p>This equation is balanced because it contains equal numbers of atoms of each element on both sides. On the left, there are two nitrogen atoms and six hydrogen atoms. On the right, two molecules of ammonia (NH\u2083) each contain one nitrogen and three hydrogen atoms, totaling two nitrogen atoms and six hydrogen atoms. This satisfies the law of conservation of mass. The other options either misrepresent the number of atoms or require adjustment in coefficients to achieve balance. Thus, Option C stands as the correct choice due to its accurate reflection of reactant-product equivalence in a chemical reaction.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-933.jpeg\" alt=\"\" class=\"wp-image-37619\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-933.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-933-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-933-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>&nbsp;The combustion reaction for propane The Correct Answer and Explanation is: Here are the correct answers followed by a detailed explanation: Question 6 Answer: C. 5 moles of O\u2082 are required Question 7 Answer: C. N\u2082 + 3 H\u2082 \u2192 2 NH\u2083 Explanation For Question 6, we are analyzing the complete combustion of propane, which [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-37617","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/37617","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=37617"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/37617\/revisions"}],"predecessor-version":[{"id":37620,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/37617\/revisions\/37620"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=37617"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=37617"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=37617"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}