{"id":37579,"date":"2025-06-26T02:49:43","date_gmt":"2025-06-26T02:49:43","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=37579"},"modified":"2025-06-26T02:49:44","modified_gmt":"2025-06-26T02:49:44","slug":"write-the-ions-present-in-the-solution-na2co3-express-answers-as-chemical-formulas-separated-by-commas","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/write-the-ions-present-in-the-solution-na2co3-express-answers-as-chemical-formulas-separated-by-commas\/","title":{"rendered":"Write the ions present in the solution Na2CO3\u2026..express answers as chemical formulas separated by commas."},"content":{"rendered":"\n<p>Write the ions present in the solution Na2CO3\u2026..express answers as chemical formulas separated by commas.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Answer:<\/strong><br>Na\u207a, CO\u2083\u00b2\u207b<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Explanation:<\/strong><\/p>\n\n\n\n<p>When <strong>sodium carbonate (Na\u2082CO\u2083)<\/strong> dissolves in water, it dissociates completely into its constituent ions because it is a soluble ionic compound. The formula <strong>Na\u2082CO\u2083<\/strong> indicates that each formula unit contains <strong>two sodium ions (Na\u207a)<\/strong> and <strong>one carbonate ion (CO\u2083\u00b2\u207b)<\/strong>.<\/p>\n\n\n\n<p>The dissociation reaction in water is:<\/p>\n\n\n\n<p><strong>Na\u2082CO\u2083 (aq) \u2192 2 Na\u207a (aq) + CO\u2083\u00b2\u207b (aq)<\/strong><\/p>\n\n\n\n<p>This equation shows that one unit of sodium carbonate produces two sodium ions and one carbonate ion when it dissolves in water.<\/p>\n\n\n\n<p>Let\u2019s break this down further:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Sodium ions (<strong>Na\u207a<\/strong>) are monovalent cations, meaning they have a single positive charge. Since there are two sodium atoms in Na\u2082CO\u2083, two Na\u207a ions are released.<\/li>\n\n\n\n<li>Carbonate ion (<strong>CO\u2083\u00b2\u207b<\/strong>) is a polyatomic ion with a charge of minus two. It remains intact in aqueous solution and balances the charge of the two Na\u207a ions.<\/li>\n<\/ul>\n\n\n\n<p>Because sodium carbonate is classified as a strong electrolyte, it dissociates completely in solution. Therefore, the only species present in significant amounts are the free ions. There are no Na\u2082CO\u2083 molecules floating around in solution, only <strong>Na\u207a<\/strong> and <strong>CO\u2083\u00b2\u207b<\/strong> ions.<\/p>\n\n\n\n<p>These ions can conduct electricity in the solution, which is one of the reasons sodium carbonate is often used in laboratory and industrial applications that require conductive solutions.<\/p>\n\n\n\n<p>In summary, the ions present in an aqueous solution of sodium carbonate are:<br><strong>Na\u207a, CO\u2083\u00b2\u207b<\/strong><\/p>\n\n\n\n<p>This shows a total dissociation of the salt into its individual ionic components.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-923.jpeg\" alt=\"\" class=\"wp-image-37580\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-923.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-923-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-923-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Write the ions present in the solution Na2CO3\u2026..express answers as chemical formulas separated by commas. The Correct Answer and Explanation is: Answer:Na\u207a, CO\u2083\u00b2\u207b Explanation: When sodium carbonate (Na\u2082CO\u2083) dissolves in water, it dissociates completely into its constituent ions because it is a soluble ionic compound. The formula Na\u2082CO\u2083 indicates that each formula unit contains two [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-37579","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/37579","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=37579"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/37579\/revisions"}],"predecessor-version":[{"id":37581,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/37579\/revisions\/37581"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=37579"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=37579"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=37579"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}