Balanced Chemical Equation for the Complete Combustion of Hexane (l):<\/strong> Explanation (300 words):<\/strong><\/p>\n\n\n\n Complete combustion is a chemical reaction where a hydrocarbon reacts fully with oxygen to produce carbon dioxide and water. In this case, the hydrocarbon is hexane, which has the chemical formula C\u2086H\u2081\u2084. Hexane is a liquid alkane consisting of six carbon atoms and fourteen hydrogen atoms. The goal of complete combustion is to ensure all carbon becomes carbon dioxide and all hydrogen becomes water.<\/p>\n\n\n\n To balance the equation, begin by writing the unbalanced form: Start with carbon atoms. Hexane has 6 carbon atoms, so the equation must produce 6 CO\u2082 molecules: Next, balance the hydrogen atoms. Hexane has 14 hydrogen atoms, so the equation must produce 7 H\u2082O molecules: Now count the total oxygen atoms on the right side. There are 6 CO\u2082 (6\u00d72 = 12 oxygen atoms) and 7 H\u2082O (7\u00d71 = 7 oxygen atoms), giving a total of 19 oxygen atoms. Since each O\u2082 molecule contains 2 oxygen atoms, 19 \u00f7 2 = 9.5 O\u2082 molecules are required.<\/p>\n\n\n\n To eliminate the fraction, multiply the entire equation by 2: This is now the balanced equation for the complete combustion of liquid hexane. This reaction is exothermic, releasing a large amount of heat, which makes hexane a useful fuel. Complete combustion requires sufficient oxygen; otherwise, incomplete combustion occurs, producing carbon monoxide or soot, which are hazardous byproducts.<\/p>\n\n\n\n Write the balanced chemical equation for the complete combustion of hexane (l). The correct answer and explanation is: Balanced Chemical Equation for the Complete Combustion of Hexane (l):2 C\u2086H\u2081\u2084 (l) + 19 O\u2082 (g) \u2192 12 CO\u2082 (g) + 14 H\u2082O (g) Explanation (300 words): Complete combustion is a chemical reaction where a hydrocarbon reacts […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-37443","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/37443","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=37443"}],"version-history":[{"count":2,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/37443\/revisions"}],"predecessor-version":[{"id":37549,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/37443\/revisions\/37549"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=37443"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=37443"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=37443"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
2 C\u2086H\u2081\u2084 (l) + 19 O\u2082 (g) \u2192 12 CO\u2082 (g) + 14 H\u2082O (g)<\/strong><\/p>\n\n\n\n
C\u2086H\u2081\u2084 + O\u2082 \u2192 CO\u2082 + H\u2082O<\/p>\n\n\n\n
C\u2086H\u2081\u2084 + O\u2082 \u2192 6 CO\u2082 + H\u2082O<\/p>\n\n\n\n
C\u2086H\u2081\u2084 + O\u2082 \u2192 6 CO\u2082 + 7 H\u2082O<\/p>\n\n\n\n
2 C\u2086H\u2081\u2084 + 19 O\u2082 \u2192 12 CO\u2082 + 14 H\u2082O<\/p>\n\n\n\n![\"\"](\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-892.jpeg\")
<\/figure>\n","protected":false},"excerpt":{"rendered":"