{"id":36733,"date":"2025-06-25T08:59:05","date_gmt":"2025-06-25T08:59:05","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=36733"},"modified":"2025-06-25T08:59:07","modified_gmt":"2025-06-25T08:59:07","slug":"given-2-0-moles-of-barium-phophate-ba3po42-how-many-moles-of-phosphorous-p-are-present","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/given-2-0-moles-of-barium-phophate-ba3po42-how-many-moles-of-phosphorous-p-are-present\/","title":{"rendered":"Given 2.0 moles of Barium Phophate, Ba3(PO4)2, how many moles of phosphorous (P) are present"},"content":{"rendered":"\n<p>Given 2.0 moles of Barium Phophate, Ba3(PO4)2, how many moles of phosphorous (P) are present?<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Correct Answer: 4.0 moles of phosphorus (P)<\/strong><\/p>\n\n\n\n<p><strong>Explanation:<\/strong><\/p>\n\n\n\n<p>To find the number of moles of phosphorus in 2.0 moles of barium phosphate, it is important to start by analyzing the chemical formula: <strong>Ba\u2083(PO\u2084)\u2082<\/strong>.<\/p>\n\n\n\n<p>This compound is made of three barium (Ba\u00b2\u207a) ions and two phosphate (PO\u2084\u00b3\u207b) ions. Each phosphate ion contains <strong>one atom of phosphorus (P)<\/strong>.<\/p>\n\n\n\n<p>So, in <strong>one formula unit<\/strong> of Ba\u2083(PO\u2084)\u2082, there are:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>2 phosphate ions \u00d7 1 phosphorus atom per phosphate = <strong>2 phosphorus atoms<\/strong><\/li>\n<\/ul>\n\n\n\n<p>This means:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>1 mole of Ba\u2083(PO\u2084)\u2082 contains 2 moles of phosphorus atoms<\/strong><\/li>\n<\/ul>\n\n\n\n<p>Now, if the sample contains <strong>2.0 moles of Ba\u2083(PO\u2084)\u2082<\/strong>, the number of moles of phosphorus is:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>2.0 moles of Ba\u2083(PO\u2084)\u2082 \u00d7 2 moles of P \/ 1 mole of Ba\u2083(PO\u2084)\u2082 = <strong>4.0 moles of phosphorus atoms<\/strong><\/li>\n<\/ul>\n\n\n\n<p>This calculation uses the concept of <strong>mole ratios<\/strong>, which helps in converting between the amount of a compound and the amount of specific elements within it.<\/p>\n\n\n\n<p>Understanding mole ratios is key to interpreting chemical formulas. The subscripts in the formula (like the 3 in Ba\u2083 and 2 in (PO\u2084)\u2082) show how many atoms or groups are in each molecule or formula unit. In Ba\u2083(PO\u2084)\u2082, the 2 after the phosphate group means there are two phosphate ions, and each phosphate contains one phosphorus atom. That leads to a total of two phosphorus atoms per unit.<\/p>\n\n\n\n<p>Therefore, with 2.0 moles of barium phosphate, there are <strong>4.0 moles of phosphorus atoms<\/strong> present.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Given 2.0 moles of Barium Phophate, Ba3(PO4)2, how many moles of phosphorous (P) are present? The correct answer and explanation is: Correct Answer: 4.0 moles of phosphorus (P) Explanation: To find the number of moles of phosphorus in 2.0 moles of barium phosphate, it is important to start by analyzing the chemical formula: Ba\u2083(PO\u2084)\u2082. This [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-36733","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/36733","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=36733"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/36733\/revisions"}],"predecessor-version":[{"id":36734,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/36733\/revisions\/36734"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=36733"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=36733"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=36733"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}