{"id":36330,"date":"2025-06-25T06:42:54","date_gmt":"2025-06-25T06:42:54","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=36330"},"modified":"2025-06-25T06:42:56","modified_gmt":"2025-06-25T06:42:56","slug":"calculate-the-mass-of-so42-present-in-2-0-g-of-baso4","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/calculate-the-mass-of-so42-present-in-2-0-g-of-baso4\/","title":{"rendered":"Calculate the mass of SO42- present in 2.0 g of BaSO4."},"content":{"rendered":"\n<p>Calculate the mass of SO42- present in 2.0 g of BaSO4. Show your work.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To calculate the mass of sulfate ion (SO\u2084\u00b2\u207b) present in 2.0 grams of barium sulfate (BaSO\u2084), we follow these steps:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 1: Find the molar mass of BaSO\u2084<\/strong><\/h3>\n\n\n\n<p>To find this, we add the atomic masses of each element in BaSO\u2084:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Barium (Ba) = 137.33 g\/mol<\/li>\n\n\n\n<li>Sulfur (S) = 32.07 g\/mol<\/li>\n\n\n\n<li>Oxygen (O) = 16.00 g\/mol \u00d7 4 = 64.00 g\/mol<\/li>\n<\/ul>\n\n\n\n<p><strong>Molar mass of BaSO\u2084 = 137.33 + 32.07 + 64.00 = 233.40 g\/mol<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 2: Determine the fraction of SO\u2084\u00b2\u207b in BaSO\u2084<\/strong><\/h3>\n\n\n\n<p>The molar mass of SO\u2084\u00b2\u207b is the mass of sulfur plus the mass of four oxygen atoms:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>SO\u2084\u00b2\u207b = 32.07 + 64.00 = <strong>96.07 g\/mol<\/strong><\/li>\n<\/ul>\n\n\n\n<p>Now, find what fraction of the total molar mass this is:<\/p>\n\n\n\n<p><strong>Fraction of SO\u2084\u00b2\u207b = (96.07 g\/mol) \/ (233.40 g\/mol) \u2248 0.4115<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 3: Calculate the mass of SO\u2084\u00b2\u207b in 2.0 g of BaSO\u2084<\/strong><\/h3>\n\n\n\n<p>Use the fraction above:<\/p>\n\n\n\n<p><strong>Mass of SO\u2084\u00b2\u207b = 0.4115 \u00d7 2.0 g = 0.823 g<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 <strong>Final Answer: The mass of SO\u2084\u00b2\u207b in 2.0 g of BaSO\u2084 is approximately 0.823 grams.<\/strong><\/h3>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation<\/strong><\/h3>\n\n\n\n<p>Barium sulfate (BaSO\u2084) is an ionic compound made of a barium ion (Ba\u00b2\u207a) and a sulfate ion (SO\u2084\u00b2\u207b). When asked to find the mass of the sulfate ion in a sample of BaSO\u2084, we must first understand the composition and molar mass of the compound. This allows us to determine what portion of the total mass is due to the sulfate group.<\/p>\n\n\n\n<p>The atomic masses used come from the periodic table. Barium is a heavy element, contributing significantly to the total mass of the compound. Sulfur and oxygen, though lighter, still make up a considerable part of the mass due to the presence of four oxygen atoms in SO\u2084\u00b2\u207b.<\/p>\n\n\n\n<p>Once the molar mass of BaSO\u2084 is calculated, we isolate the molar mass of SO\u2084\u00b2\u207b and find its proportion in the whole compound. Multiplying this fraction by the actual mass of the sample (2.0 g) gives the mass of sulfate in the sample.<\/p>\n\n\n\n<p>This method is a direct application of the concept of percent composition in chemistry. It is useful in analytical work and stoichiometry when you need to determine how much of a certain ion or element is present in a given compound. Understanding this calculation also helps in interpreting chemical formulas and performing more advanced quantitative chemical analyses.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-786.jpeg\" alt=\"\" class=\"wp-image-36336\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-786.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-786-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-786-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Calculate the mass of SO42- present in 2.0 g of BaSO4. Show your work. The Correct Answer and Explanation is: To calculate the mass of sulfate ion (SO\u2084\u00b2\u207b) present in 2.0 grams of barium sulfate (BaSO\u2084), we follow these steps: Step 1: Find the molar mass of BaSO\u2084 To find this, we add the atomic [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-36330","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/36330","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=36330"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/36330\/revisions"}],"predecessor-version":[{"id":36337,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/36330\/revisions\/36337"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=36330"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=36330"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=36330"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}