{"id":35245,"date":"2025-06-24T08:39:29","date_gmt":"2025-06-24T08:39:29","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=35245"},"modified":"2025-06-24T08:39:31","modified_gmt":"2025-06-24T08:39:31","slug":"draw-the-molecular-orbital-diagram-for-the-fluorine-molecule-f2","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/draw-the-molecular-orbital-diagram-for-the-fluorine-molecule-f2\/","title":{"rendered":"Draw the molecular orbital diagram for the fluorine molecule (F2)."},"content":{"rendered":"\n<pre id=\"preorder-ask-header-text\" class=\"wp-block-preformatted\"> Draw the molecular orbital diagram for the fluorine molecule (F2). Calculate the bond order and provide a concise statement to describe whether the bond order aligns with what you would predict based on the Lewis structure of\u00a0F2.<\/pre>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To answer this question, we will draw the molecular orbital (MO) diagram for the fluorine molecule (F\u2082), calculate its bond order, and compare it to the prediction from the Lewis structure.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Molecular Orbital Diagram for F\u2082<\/strong><\/h3>\n\n\n\n<p>Fluorine has 9 electrons. In F\u2082, each atom contributes 9 electrons, making a total of 18 electrons. Only the valence electrons (2s and 2p orbitals) are considered in the MO diagram, which totals 14 valence electrons (7 from each atom).<\/p>\n\n\n\n<p><strong>Order of Molecular Orbitals for F\u2082 (Z \u2265 8):<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>\u03c3(2s)<\/li>\n\n\n\n<li>\u03c3*(2s)<\/li>\n\n\n\n<li>\u03c3(2p\u2093)<\/li>\n\n\n\n<li>\u03c0(2p_y), \u03c0(2p_z)<\/li>\n\n\n\n<li>\u03c0*(2p_y), \u03c0*(2p_z)<\/li>\n\n\n\n<li>\u03c3*(2p\u2093)<\/li>\n<\/ul>\n\n\n\n<p><strong>Electron Filling:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>\u03c3(2s): 2 electrons<\/li>\n\n\n\n<li>\u03c3*(2s): 2 electrons<\/li>\n\n\n\n<li>\u03c3(2p\u2093): 2 electrons<\/li>\n\n\n\n<li>\u03c0(2p_y), \u03c0(2p_z): 4 electrons<\/li>\n\n\n\n<li>\u03c0*(2p_y), \u03c0*(2p_z): 4 electrons<\/li>\n\n\n\n<li>\u03c3*(2p\u2093): 0 electrons<\/li>\n<\/ul>\n\n\n\n<p>All 14 valence electrons are now placed.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Bond Order Calculation<\/strong><\/h3>\n\n\n\n<p>Bond order = (Number of bonding electrons &#8211; Number of antibonding electrons) \/ 2<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Bonding electrons = 2 (\u03c32s) + 2 (\u03c32p\u2093) + 4 (\u03c02p) = 8<\/li>\n\n\n\n<li>Antibonding electrons = 2 (\u03c3<em>2s) + 4 (\u03c0<\/em>2p) = 6<\/li>\n<\/ul>\n\n\n\n<p>Bond order = (8 &#8211; 6) \/ 2 = <strong>1<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Comparison with Lewis Structure<\/strong><\/h3>\n\n\n\n<p>The Lewis structure of F\u2082 shows a single bond between the two fluorine atoms, which is consistent with a bond order of 1. The molecular orbital diagram confirms this, showing one net bond between the atoms after canceling out the bonding and antibonding effects. Thus, the MO theory and Lewis structure both predict the same type of bonding in F\u2082. This reinforces the reliability of both models for simple diatomic molecules like fluorine.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-651.jpeg\" alt=\"\" class=\"wp-image-35246\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-651.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-651-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-651-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Draw the molecular orbital diagram for the fluorine molecule (F2). Calculate the bond order and provide a concise statement to describe whether the bond order aligns with what you would predict based on the Lewis structure of\u00a0F2. The Correct Answer and Explanation is: To answer this question, we will draw the molecular orbital (MO) diagram [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-35245","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/35245","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=35245"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/35245\/revisions"}],"predecessor-version":[{"id":35247,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/35245\/revisions\/35247"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=35245"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=35245"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=35245"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}